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alexgriva [62]
3 years ago
7

Prove that..please help​

Physics
1 answer:
GaryK [48]3 years ago
8 0

\large{ \boxed{ \bf{ \color{red}{Universal \: law \: of \: gravitation}}}}

Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The forces along the line joining the centre of the two objects.

❍ Let us consider two masses m1 and m2 line at a separation distance d. Let the force of attraction between the two objects be F.

According to universal law of gravitation,

\large{ \longrightarrow{ \rm{F \propto m_1 m_2}}}

Also,

\large{ \longrightarrow{ \rm{ F \propto  \dfrac{1}{ {d}^{2} } }}}

Combining both, We will get

\large{ \longrightarrow{ \rm{F  \propto  \dfrac{ m_1 m_2}{ {d}^{2}}}}}

Or, We can write it as,

\large{ \longrightarrow{ \rm{F  \propto  \:  G \dfrac{ m_1 m_2}{ {d}^{2} }}}}

Where, G is the constant of proportionality and it is called 'Universal Gravitational constant'.

☯️ Hence, derived !!

<u>━━━━━━━━━━━━━━━━━━━━</u>

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Which option is the most accurate description of speed?
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B I think is the answer
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A clindrical rod of uniform density is located with its center at the origin, and its axis along the axis. It rotates about its
zhenek [66]

Answer:

6093.2328 J

Explanation:

For cylindrical rod moment of inertia will be

I_X=I_Y=\frac{1}{12}m(3r^2+h^2)

I_X=I_Y=\frac{1}{12}\times 4(3\times 0.06^2+0.6^2)=0.1236 kg -m^2

we have given time =0.02 sec

Angular speed =\frac{2\pi }{T}=\frac{2\times 3.14}{0.02}=314\ rad/sec

Rotational KE = \frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.1236\times 314^2=6093.2328\ J

5 0
4 years ago
The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object
Gennadij [26K]
Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation:   1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.
3 0
4 years ago
Read 2 more answers
How much does a bowling ball weigh if it has a mass of 6 kg on Earth?
larisa [96]

Answer: pretty sure 14 pounds

Explanation:

7 0
3 years ago
4. A car of mass 2000 kg is traveling at 45 m/s when the driver spots a policeman anead. i ne univer apprivo
MariettaO [177]

Answer:

The change in the Kinetic Energy of the car, E = 1449000 joules

Explanation:

Given,

The mass of the car, m = 2000 Kg

The speed of the car, v = 45 m/s

The brake applied on the car for a duration, t = 3 s

The average force applied by the brake, F = 1.4 x 10⁴ N

The kinetic energy of the body is given by the relation,

                                     K.E = 1/2 mv²

The initial kinetic energy of the car,

                                   K.E = 0.5 x 2000 x 45

                                          = 2025000 J

The force applied by the brakes

                                   F = m x a

Therefore, the deceleration of the car

                                     a = F / m

                                        = 1.4 x 10⁴ / 2000

                                       = 7 m/s²

Using the first equations of motion,

                                 v = u + at

                                 v = 45 + (-7) (3)                      ∵  (-7 ) car is decelerating

                                  v =24 m/s

The final kinetic energy of the car

                                 k.e = 0.5 x 2000 x 24

                                        = 576000 J

The difference in the kinetic energy,

                           E = K.E - k.e

                               = 2025000 J - 576000 J

                               = 1449000 joules

Hence, the change in the Kinetic Energy of the car, E = 1449000 joules

3 0
3 years ago
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