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babymother [125]
4 years ago
7

An antacid tablet was dissolved in water and 10mL of 0.16M HCl was added. After the acid had reacted with the tablet it required

40mL of 0.02M NaOH to neutralize the HCl that remained. How many moles of HCl did the antacid neutralize
Chemistry
1 answer:
Mnenie [13.5K]4 years ago
7 0

Answer:

0.0008 mole of HCl

Explanation:

From the balanced equation between HCl and NaOH:

HCl + NaOH --> NaCl + H_2O

1 mole of acid requires 1 mole of base for neutralization.

mole = molarity x volume

mole of NaOH = 0.02 x 0.04 = 0.0008 mole

mole HCl = 0.16 x 0.01 = 0.0016 mole

Since 1 mole of NaOH requires 1 mole of HCl for neutralization, it means that 0.0008 mole of NaOH will require 0.0008 mole of HCl. The remaining mole of HCl must have been neutralized by the antiacid:

0.0016 - 0.0008 = 0.0008 mole.

Therefore, 0.0008 mole of HCl must have been neutralized by the antiacid.

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Explanation:

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3 years ago
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Carbon-14 has a half-life of 5,730 years. If scientists discover a mummified Cro-Magnon specimen, they will first want to determ
ryzh [129]

Answer:

the specimen has 11460 years old

Explanation:

if the live sample has as initial amount of Yo C14, the dead sample will have 0.25Yo of C14.

the rate of decay of radiactive matter over time is

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⇒ t = 11460 year

4 0
3 years ago
What volume will 1.25 liters of carbon dioxide occupy at 50.0°C if the pressure changes from 0.865 atm to 0.820 atm?
Elena-2011 [213]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 = P2V2

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V2 = 0.865 x 1.25 / 0.820

V2 = 1.32 L

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