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navik [9.2K]
3 years ago
10

What is the limiting reactant if 8 g of Ba reacts with 2.8 g of Al2(SO4)3?

Chemistry
1 answer:
Nata [24]3 years ago
5 0

Answer:

Al2(SO4)3 is the limiting reactant

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3Ba + Al2(SO4)3 → 2Al + 3BaSO4

Next, we shall determine the mass of Ba and the mass of Al2(SO4)3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Ba = 137g/mol

Mass of Ba from the balanced equation = 3 x 137 = 411g

Molar mass of Al2(SO4)3 = 2x27 + 3[32 + (16x4)]

= 54 + 3[32 + 64]

= 54 + 3[96]

= 54 + 288 = 342g/mol

Mass of Al2(SO4)3 from the balanced equation = 1 x 342 = 342g

Summary:

From the balanced equation above,

411g of Ba reacted with 342g of Al2(SO4)3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above,

411g of Ba reacted with 342g of Al2(SO4)3.

Therefore, 8g of Ba will react with

= (8 x 342/411 = 6.66g of Al2(SO4)3.

From the calculations made above, we can see that it will take a higher mass of Al2(SO4)3 i.e 6.66g than what was given i.e 2.8g to react completely with 8g of Ba.

Therefore, Al2(SO4)3 is the limiting reactant and Ba is the excess reactant.

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Answer:

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weather and environmental factors, your surroundings and orders related to the environment basically

6 0
2 years ago
A cube has a mass of 42 grams and a volume of 15 cubic centimeters. What is it’s density?
deff fn [24]

Answer:

2.8g/cm³

Explanation:

Given parameters:

Mass of cube = 42g

Volume of cube  = 15cm³

Unknown:

Density of the cube  = ?

Solution:

Density is defined as the mass per unit volume of a substance. It is mathematically expressed as:

 Density  = \frac{mass}{volume}  

So;

 Density  = \frac{42}{15}   = 2.8g/cm³

6 0
3 years ago
What changes if the degree (amount) of intermolecular bonds of a substance are changed?
elixir [45]
<h2>Answer:</h2>

The correct answers are;

volume of a substance

density of a substance

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7 0
3 years ago
Read 2 more answers
6.How many moles of gas would be in contained in a 11.2 L container that is at a
qaws [65]

0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated using the following expression:

PV = nRT

Where;

  • p = pressure (atm)
  • v = volume (L)
  • n = number of moles
  • R = gas law constant
  • T = temperature

0.75 × 11.2 = n × 0.0821 × 300

8.4 = 24.63n

n = 8.4 ÷ 24.63

n = 0.34 moles

Therefore, 0.34 moles of gas would be contained in a 11.2 L container that is at a pressure of 0.75 atm and 300 K.

Learn more about number of moles at: brainly.com/question/1190311

4 0
1 year ago
What is the average Volume of a single penny from the total 25 penny data?
mojhsa [17]

Answer:

1.16 mL  

Explanation:

Assume the data show that 25 pennies have a total volume of 29.00 mL.

\text{Average volume} = \dfrac{\text{29.00 mL}}{25} = \textbf{1.16 mL}

7 0
3 years ago
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