I think in this situation the best method would be a guess and check. You know that there are 8 dimes more than there are nickels. So just keep increasing each number by one until you reach $1.40. If there were 9 dimes and 1 nickels it would add up to $0.95. If there were 10 dimes and 2 nickels, it would add up to $1.10. If there were 11 dimes and 3 nickels, it would add up to $1.25. If there were 12 dimes and 4 nickels, it would add up to $1.40. So your answer is 12 dimes and 4 nickels.
I hope this helped!
Answer is below..............
Answer:
For 
, x = 2, or x = - 2.
Step-by-step explanation:
Here, the given expression is :
Now, using the ALGEBRAIC IDENTITY:
Comparing this with the above expression, we get
⇒Either (x-2) = 0 , or ( x + 2) = 0
So, if ( x- 2) = 0 ⇒ x = 2
and if ( x + 2) = 0 ⇒ x = -2
Hence, for , x = 2, or x = - 2.
Answer:
4 1/12
Step-by-step explanation:
make all the denominators 12 so u can add them easier
2 1/12 + 2 4/12 + 3 2/12 = 7 7/12
nn subtract from the 11 2/3
11 8/12 - 7 7/12 = 4 1/12
Answer:
7-3n
Step-by-step explanation:
Im pretty sure this is the right answer
