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3 years ago

Divisions of fractions by fractions

Mathematics

1 answer:

belka [17]3 years ago

4 0

You would have to flip the fractions and then multiply the top numbers and the bottom numbers

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RR + RR = 50 RR + sss = 33 sss + sss = 16 RRR + ss x R + RsR =

Morgarella [4.7K]

Answer:

Step-by-step explanation:

Alright so here is what I came up with

25 + 25 = 50 + -17 = 33 -10 + -7 = 16

I couldnt figure out the rest hopefully this can assist you a tad bit

4 0

4 years ago

Can u help solve these questions please

Tasya [4]

Answer:

Step-by-step explanation:

$\sqrt[4]{(16a^4)^5}=(16a^4)^{\frac{5}{4}}$ [Since, $\sqrt[n]{x}=x^{\frac{1}{n}}$ ]

$=(16)^{\frac{5}{4}}(a^4)^{\frac{5}{4}}$

$=(2^4)^{\frac{5}{4}}(a^4)^{\frac{5}{4} }$

$=(2^{4\times \frac{5}{4}})(a^{4\times \frac{5}{4}})$

$=2^5a^5$

$\sqrt[5]{(b^{\frac{1}{4}})^6}=\sqrt[5]{b^{\frac{6}{4}}}$

$=\sqrt[5]{b^{\frac{3}{2}}}$

$=(b^{\frac{3}{2}})^{\frac{1}{5} }$

$=b^{\frac{3}{10}}$

$\sqrt[3]{\frac{c^{15}}{c^9}}=\sqrt[3]{c^{15-9}}$

$=(c^6)^{\frac{1}{3}}$

$=c^{6\times \frac{1}{3} }$

= c²

$\sqrt[4]{16d^6\times 16d^{-5}}=\sqrt[4]{(2)^4(d^{6-5})(2)^4}$

$=\sqrt[4]{2^{(4+4)}d}$

$=\sqrt[4]{(2^8)d}$

$=2^{\frac{8}{4}}d^{\frac{1}{4}}$

$=2^2d^{\frac{1}{4}}$

$=4d^{\frac{1}{4}}$

8 0

3 years ago

I dont know the answer i have tried everything

shusha [124]

Answer:

Total area = 12x^2 + 2x

Perimeter = 18x+4

Step-by-step explanation:

Divide the figure into two separate shapes to make the question easier.

Area = lw

Area (bigger shape) = (3x)(3x)

Area (bigger shape) = 9x^2

Area = lw

Area (smaller shape) = (3x+2)(x)

Area (smaller shape) = 3x^2+2x

Add the areas of the bigger and smaller shapes to get the total area:

Total area = 9x^2 + 3x^2 + 2x

Total area = 12x^2 + 2x

To find the perimeter, add the lengths of all the sides.

(3x)+(3x)+(3x)+(3x)+(3x+2)+(3x+2)

(12x)+(6x+4)

perimeter = 18x+4

8 0

2 years ago

The perimeter P (in yards) of a soccer field is represented by the formula = 2 + 2, where is the length (in yards) and is the wi

aliya0001 [1]

Answer:

$W=(\frac{P}{2}-L)\ yd$

Step-by-step explanation:

we know that

The perimeter P (in yards) of a soccer field is

$P=2L+2W$

where

L is the length in yards

W is the width in yards

Solve the equation for the width W

That means -----> isolate the variable W

Subtract 2L both sides

$P-2L=2W$

Divide by 2 both sides

$W=(\frac{P}{2}-L)\ yd$

4 0

3 years ago

I need help bc good at every class but math

Kobotan [32]

Answer:

Step-by-step explanation:

5 0

2 years ago

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