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konstantin123 [22]
2 years ago
9

Find the sum of the first 10 terms of the following series, to the nearest integer.

Mathematics
1 answer:
Alona [7]2 years ago
4 0

Answer:

Step-by-step explanation:

you can see this is a geometric progression which a ratio of {2\over{5}}. the sum of the firs n term is:

S=a_1\frac{(1-r^n)}{(1-r)}=175\frac{1-(\frac{2}{5})^{10}}{1-\frac{2}{5}}=291.6360832

the nearest integer would be:

292

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Answer:

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Ugo [173]

Answer:

25. 27a^{3}b^{2}

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Step-by-step explanation:

For 25:

A = \frac{a+b}{2} h  (area of a trapezoid)

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For 26:

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3 years ago
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