Solve for x. -1/2 (x+5) = 2x -3/2

A shelf has different sizes of bottles of laundry detergent. This line plot shows the number of cups of laundry detergent in eac

salantis [7]

Answer:

2 / 3 loads

Step-by-step explanation:

From. The plot, we can conclude that, the detergent that has the most bottles is that with 5 ; the number of cups in the detergent with 5 bottles is 12 cups

Number of cups used for each load of laundry = 18 cups

The loads of laundry Eric can do is thus :

Number of cups of detergent / number of cups used for each load of laundry

= 12 / 18

= 2 / 3 loads

8 0

2 years ago

Is V72 rational or irrational? And why

Evgesh-ka [11]

Irrational, because if you simplify the root V72=6V2

7 0

2 years ago

PLEASE HELP!!!!

Paraphin [41]

Answer:

yes

Step-by-step explanation:

1 is smaller than ten

5 0

2 years ago

Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded

Whitepunk [10]

Answer:

<h3>The answer is 17.5 units</h3>

Step-by-step explanation:

Using the distance formula

the distance between (-10, 12) and (5, 3) is

d = 17.492855

We have the final answer as

<h3>d = 17.5 units to the nearest tenth</h3>

Hope this helps you

4 0

2 years ago

Read 2 more answers

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

2 years ago