Answer:
c because the x value is equal to the y value
Step-by-step explanation:
Answer:
The probability that they will both be on time is 12/25.
Step-by-step explanation:
John is late 20% of the time.
So, he is prompt 80% of the time.
Ted is late 40% of the time.
So, he is prompt 60% of the time.
Since, both the events are independent,
p(John be on time ∩ Ted be on time) = p(John be on time) × p(Ted be on time)
× 
= 0.80 × 0.60
= 0.48 or 48%

Hence, the probability that they will both be on time is 12/25.
Answer:6018
Step-by-step explanation:
Given Sequence

It represent an A.P. with
first term 
common difference 
So sum of 51 term
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B2%5Ctimes%20%28-282%29%2B%2851-1%2916%5D)
![S_{51}=\frac{51}{2}\times [-564+800]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B-564%2B800%5D)
![S_{51}=\frac{51}{2}\times [236]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B236%5D)


Answer:
The sample space
Step-by-step explanation:
By definition, the sample space is the set composed by all the possible outcomes of your random variable. In this case, the random variable is 4 sided dice, so the sample space is

Answer:
J
Step-by-step explanation:
You can see that one of the rings was originally $24 and on sale it is $18 which is 3/4 or 0.75 of 24. Then if you check that relationship with the other ones where you take the orginal price and find 3/4 or 0.75 of it you get all of the sale prices.