a. Only a Hamiltonian path
One such path is
1 → 2 → 0 → 4 → 3
which satisfies the requirement that each vertex is visited exactly once.
There is no Hamiltonian circuit, however, since it is impossible for any Hamiltonian path on this graph to visit vertex 0 exactly once.
Answer:
-19
Step-by-step explanation:
-11+(-8)
-11-8
-19
hole this is correct
Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...
126/42=378/126=1134/378=3
The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:
42=a(3)^(2-1)
42=3a
a=14
So the first term is 14.
Answer:
Q1: 2nd row 2nd tile
Q2: 1st row 1st tile
Q3: 1st row 3rd tile
Q4: 2nd row 3rd tile
Step-by-step explanation:
When
Vertex is (-p, q)
