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oksano4ka [1.4K]
3 years ago
15

Which expression represents the composition [f o g o h](x) for the functions below? f(x) = –2x^4 g(x) = 4x – 6 h(x) = x – 1

Mathematics
2 answers:
pantera1 [17]3 years ago
6 0
The expression would be -2( 4 (x-1) - 6 )^4.

BARSIC [14]3 years ago
5 0

Answer: A. -2(4x-10)^4 on edge :)

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A triangle has two sides of lengths 7 and 12. What value could the length of
Norma-Jean [14]

Answer:

A. 7

Step-by-step explanation:

Since the triangle sides are not defined, therefore let the base side have the 12 unit and one of the slant side be 7 unit.

Therefore height of the triangle, h can gotten from the Pythagoras theorem as thus:

7² = (12/2)² + h²

49 = 36 + h²

h² = 49 - 36 = 13

h = √13

knowing the height of the triangle, we can apply same rule to the other unknown slant side, x as thus:

x² = (12/2)² + h²

x² = 36 + 13 = 49

x = √49

x = 7

4 0
3 years ago
Subtract:
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Answer:

it's answer is D -92

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3 0
3 years ago
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(ED. 21) Analytic Geometry Unit Test..... #3 Which point is a solution of x2 + y2 > 49 and y ≤ –x2 – 4?
sdas [7]

Answer:

We want to find a solution of the system:

x^2 + y^2 > 49

y ≤ –x^2 – 4

Here we do not have any options, so let's try to find a general solution.

First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:

(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

(0, -10)

(0, -15)

(2, -10)

etc.

8 0
3 years ago
Which values represent solutions to Cosine (StartFraction pi Over 4 EndFraction minus x) = StartFraction StartRoot 2 EndRoot Ove
ddd [48]

Answer:

End fraction right brace

Step-by-step explanation:

I really hope I helped GL <33!

6 0
3 years ago
A student solves the equation for v. Start with the original equation. Use the square root property. Use the division property o
LekaFEV [45]

Answer:

the answer is d

<em>The square root property should have been applied to both complete sides of the equation instead of to select variables. </em>

<em />

Step-by-step explanation: i just took the test on edge

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