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inessss [21]
3 years ago
6

Which answer includes the intervals that contain the solution to the inequality? x2-1/3x+9_<0

Mathematics
1 answer:
zmey [24]3 years ago
3 0

Answer:the correct option is D

Step-by-step explanation:

I took the test

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Solve the equation below:
Agata [3.3K]
\sqrt[3]{x^2-8}=2 \\ x^2-8=2^3=8  \\ x^2=16 \\  \\ \boxed{x=4 \ or \ -4}
6 0
3 years ago
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A boat is located a sea level. A scuba diver is 80 feet along the surface of the water from the boat and 30 feet below thw water
Sauron [17]

Given :

A boat is located a sea level. A scuba diver is 80 feet along the surface of the water from the boat and 30 feet below the water surface.

A fish is 20 feet along the horizontal plane from the scuba diver and 10 feet below the scuba diver.

To Find :

The slope between the scuba diver and fish.

Solution :

Horizontal distance between diver and fish is 20 feet.

Fish is 10 feet below the scuba diver.

Slope between scuba diver and fish is :

tan\ \theta = \dfrac{10}{20}\\\\tan\ \theta = 0.5

Therefore, the slope between the scuba diver and fish is 0.5 .

6 0
3 years ago
A University has 30,600 students think school counselor estimates that 2% of the students break three on my languages in a rando
xxTIMURxx [149]

Answer:

Counselor's estimate isn't correct.

Step-by-step explanation:

Total number of students in university = 30,600

2% break 3 of the languages

Therefore, 2/100 × 30600 = 612 students break 3 of the languages in the University according to the counselor.

In a random sample of 240 students, 20 break 3 of the languages.

% = 20/240 × 100 = 8.33%

SinceTotal number of students = 30,600

Therefore, 30,600/240 = 127.5

Which means 127.5 × 20 = 2550.

Which means 2550 students break 3 of the languages as against the 612 students stated by the counselor.

4 0
3 years ago
An observer in a hot air balloon sights a building that is 50 m from the balloon's launch point. The balloon has risen 165 m. Wh
Kaylis [27]
Notice the picture,
recall your SOH, CAH, TOA
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}&#10;\qquad \qquad &#10;% cosine&#10;cos(\theta)=\cfrac{adjacent}{hypotenuse}&#10;&#10;\\ \quad \\&#10;% tangent&#10;tan(\theta)=\cfrac{opposite}{adjacent}

you have,
opposite side, 165
adjacent side, 50
and the angle

that means, we'll need Mrs. tangent
thus 
\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(\theta)=\cfrac{165}{50}&#10;\\ \quad \\&#10; tan^{-1}\left[ tan(\theta) \right]=tan^{-1}\left[ \cfrac{165}{50} \right]&#10;\\ \quad \\&#10;\theta=tan^{-1}\left[ \cfrac{165}{50}\right]&#10;\\ \uparrow  \\&#10; \textit{angle of elevation}\iff\textit{angle of depression}

4 0
3 years ago
Use long division to divide, given the dividend and divisor: <br>(ii) 2x³ + 6x²-x+5; 2x² −1​
schepotkina [342]

Answer:

x+3+ 8/2x^2-1

Step-by-step explanation:

Hope it helps!

8 0
2 years ago
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