Three consecutive numbers are x, x+1 and x+2.
Four times the first integer is 4x
The sum of the second and third is (x+1)+(x+2)=2x+3.
So, we have

Subtract 2x from both sides:

Divide both sides by 2:

So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.
In fact, you have

and

Answer: (1,-2), (1, 3)
Step-by-step explanation:y=2x+1
Y=2(1)+1
Y=2+1
Y=3
3=2x+1
-1 -1
2=2x
_ _
2 2
X= 1 new you got your perpendicular line
So answer is (1, -2), (1, 3)
Answer:
maybe like 12
Step-by-step explanation:
I would think 12 because because it is 2 of the square so I think 6 + 6 correct me of I'm wrong.
Answer:
1:7
Step-by-step explanation: