I think you have to figure out the gradient, so you take the 2 points and put it into the equation
change in y divided by change in x aka
y2-y1/x2-x1
so for question 3:
y2=4 and y1=3
(taken from the first and second coordinates)
x2=3 and y1=7
put these values jnto the equation
4-3/3-7 = 1/-4 (can be written as negative 1/4)
for question 4 its the same thing:
y2=9 and y1=5
x2=4 and x1=2
put into equation
9-5/4-2 = 4/2
hope this helps, im also hoping your teacher already has taught this because i didnt go into detail of where the equation came from, if not ask me and ill gladly help X
Answer:
yeah, it's A your correct!
hope it helps;)
Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:
this is equivalent to:
thus, we can conclude that
x= 3.
You are going to want to cross multiply this, so 5/9 would multiply with 1 and 2/3 would be multiplied by x. Now you have 5/9 = 2/3x. You would divide 2/3 on both sides and get 5/6. 5/6 is your answer.
