An acid with a p K a of 8.0 is present in a solution with a pH of 6.0. What is the ratio of the protonated to the deprotonated f
1 answer:
Explanation:
According to the Henderson-Hasselbalch equation,
pH = +
Given values are pH = 6, = 8
Putting given values into the above equation as follows.
6 = 8 +
= -2
= antilog -2
= 0.01
But according to the question, we need protonated to deprotonated ratio of
=
= 100
Thus, we can conclude that ratio of the protonated to the deprotonated form of the acid is .
You might be interested in
Answer:
A beaker
Step-by-step explanation:
Specifically, I would use a 250 mL graduated beaker.
A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.
You don't need precisely 100 mL solution.
If the beaker is graduated, you can easily measure 100 mL of the stock solution.
Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).
