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andrey2020 [161]
2 years ago
12

The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?

Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
5 0

Answer : The volume of pure diamond is 0.493inch^3

Explanation : Given,

Density of pure carbon in diamond = 3.52g/cm^3

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}

Molar mass of carbon = 12 g/mol

\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

Density=\frac{Mass}{Volume}

Now putting all the given values in this formula, we get:

3.52g/cm^3=\frac{284.4g}{Volume}

Volume = 80.8cm^3

As we know that:

1cm^3=0.061inch^3

So,

Volume = 0.061\times 80.8inch^3

Volume = 0.493inch^3

Therefore, the volume of pure diamond is 0.493inch^3

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Explanation:

data given:

H30+= 1.40 X 10^-4 M\

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pH = -log10(H30+)

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pH = 3.85

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The OH- concentration from the pOH by the equation:

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2 years ago
g When a species can be represented by two or more resonance structures, the actual representation of bonding in the species is
AlekseyPX

Answer:

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Explanation:

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A number of equivalent structures are then used to show the nature of bonding in such a molecule. Such structures are called resonance structures or canonical structures. None of these structures individually offer a holistic explanation to the bonding interactions in the molecule under study.

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6 0
3 years ago
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2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea
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<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.0275 M

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

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Volume of container = 2.00 L

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For the given chemical equation:

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<u>At eqllm:</u>           0.275-2x      x         x

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Hence, the concentration of hydrogen gas at equilibrium is 0.0275 M

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