How do I factor by grouping this expression 32u-uv+8u^2-4v
1 answer:
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Answer:
z-score is 2.16
98.46% of men are SHORTER than 6 feet 3 inches
Step-by-step explanation:
The heights of adult men in America are normally distributed, with a mean of 69.3 inches and a standard deviation of 2.64 inches.
Mean =
Standard deviation =
a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)
x = 6 feet 3 inches
1 feet =12 inches
6 feet = 12*6 = 72 inches
So, x = 6 feet 3 inches = 72+3=75 inches
Formula :
So, his z-score is 2.16
No to find percentage of men are SHORTER than 6 feet 3 inches
We are supposed to find P(x< 6 feet 3 inches)
z-score is 2.16
Refer the z table
P(x< 6 feet 3 inches) =0.9846
So, 98.46% of men are SHORTER than 6 feet 3 inches