V = lwh
V = (x + 2)(x + 3)(x)
V = (x)(x^2 + 3x + 2x + 6)
V = (x^3 + 3x^2 + 2x^2 + 6x)
V = x^3 + 5x^2 + 6x
All you do is foil the dimensions together and then combine like terms. Hope this helps!
First, let's establish a ratio between these two values. We'll use that as a starting point. I personally find it easiest to work with ratios as fractions, so we'll set that up:

To find the distance <em>per year</em>, we'll need to find the <em>unit rate</em> of this ratio in terms of years. The word <em>unit</em> refers to the number 1 (coming from the Latin root <em>uni-</em> ); a <em>unit rate</em> involves bringing the number we're interested in down to 1 while preserving the ratio. Since we're looking for the distance the fault line moves every one year, we'll have to bring that 175 down to one, which we can do by dividing it by 175. To preserve our ratio, we also have to divide the top by 175:

We have our answer: approximately
0.14 cm or
1.4 mm per year
Answer:
B) 6
Step-by-step explanation:
f(x) = (x + 1)2
f(2) = (2 + 1)2
f(2) = 3 * 2
f(2) = 6
Answer:
120 lbs
Step-by-step explanation:
Work = force * distance
1800 ft-lb = force * 15 ft
force = 1800 ft-lb / 15 ft
=1800/15 ft-lb/ft
=120lbs
Answer:
x+2/2(2x+1)
Step-by-step explanation:
Tamlin has x male action figures and x + 2 female action figures, so a total of x + x + 2, or 2x + 2 action figures. The probability of picking two female action figures without replacement is equal to the product of the probability of
-picking 1 female action figure from the total number and
-picking 1 female action figure after 1 has been removed.
The probability of picking 1 female action figure from the total is equal to the total number of female action figures divided by the total number of action figures.
The probability of picking 1 female action figure after 1 has been removed is equal to the total number of female action figures minus 1 divided by the total number of action figures minus 1.
Multiply these two expressions and simplify.