Find the volume of a right circular cone that has a height of 2.5 ft and a base with a diameter of 5.2 ft. Round your answer to
1 answer:
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Answer:
A (3, 1/2) B (-3/2, -7/4) C (7/5, 9/2)
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The <u>correct answer </u>is:
x²+2x+3.
Explanation:
We need to divide each term of the numerator by the denominator. For the <u>first term</u>:
Dividing the coefficients, we have 5/5 = 1.
When dividing the variables, we use the quotient rule: when dividing powers that have the same base, subtract the exponents. This gives us:
x³/x = x³/x¹ = x³⁻¹ = x²
For the first monomial, this gives us 1x² = x².
The <u>second term</u>:
Dividing the coefficients, we have 10/5 = 2.
Dividing the variables, we again use the product rule:
x²/x = x²/x¹ = x²⁻¹ = x¹ = x
Together this gives us 2x.
The <u>third term</u>:
Dividing the coefficients, we have
15/5 = 3.
Dividing the variables, we have x/x; when you divide something by itself, the answer is 1. This gives us:
3*1 = 3.
Together our quotient is x²+2x+3.
x²+2x+3.
Explanation:
We need to divide each term of the numerator by the denominator. For the <u>first term</u>:
Dividing the coefficients, we have 5/5 = 1.
When dividing the variables, we use the quotient rule: when dividing powers that have the same base, subtract the exponents. This gives us:
x³/x = x³/x¹ = x³⁻¹ = x²
For the first monomial, this gives us 1x² = x².
The <u>second term</u>:
Dividing the coefficients, we have 10/5 = 2.
Dividing the variables, we again use the product rule:
x²/x = x²/x¹ = x²⁻¹ = x¹ = x
Together this gives us 2x.
The <u>third term</u>:
Dividing the coefficients, we have
15/5 = 3.
Dividing the variables, we have x/x; when you divide something by itself, the answer is 1. This gives us:
3*1 = 3.
Together our quotient is x²+2x+3.