In a game of rock paper scissors, what are the chances that someone playing against a person playing only paper would win?
As for the answer, if you were to make a chart to show rock, paper, and scissors, you'd be able to see that there's a 2/3 chance of winning by choosing rock. With scissors, there's also a 2/3 chance to win. Now with paper, there's only a 1/3 chance to win. Knowing that the other person will only play paper, the best answers would be to choose either rock or scissors.
(there are, of course, flaws with this concept, because the opponent could be lying about playing only paper. More or less, it's a good design to show probability.)
How many 3/4 cups of milk would be needed to make 21 cups of milk for a large recipe?
7 - 9w = - 29
Subtract 7 from both sides
- 9w = - 36
Divide by - 9 on both sides
w = 4
primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a
![a=\sqrt[]{hipotenusa^2-cateto^2}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7Bhipotenusa%5E2-cateto%5E2%7D)
![a=\sqrt[]{100^2-85^2}=52.68](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B%5D%7B100%5E2-85%5E2%7D%3D52.68)
a=52.68 m
teniendo el lado faltante podemos calcular las razones trigonometricas
