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CaHeK987 [17]
3 years ago
11

The sum of three consecutive numbers is 414. What is the 2nd number?

Mathematics
2 answers:
Naya [18.7K]3 years ago
5 0

The equation for what the 2nd number of three consecutive numbers that equal to 414 is : x+(x+1)+(x+2)=414

Multiply and Simplify:

x+x+1+x+2=414

3x+3=414

Subtract 3 from both sides:

3x+3-3=414-3

3x=411

Divide three by both sides to get answer:

3x/3=411/3

x=137.

If you want to check if its correct add the three numbers that come next:

137+138+139=414.

maw [93]3 years ago
5 0

Answer:  The 2nd number is 138

Step-by-step explanation:

Let x be the  first number, let 2x be the second number and let 3x be the third number

since the sum of the three consecutive numbers is 414, then this implies;

x + 2x + 3x =  414

6x            =    414

To get the value of x, we divide both-side of the equation by six(6)

6x / 6  =  414/6

(On the left-hand side of the equation, the six at the numerator will cancel out the six at the denominator leaving us with just x and the right-hand side of the equation, we will simply divide 414 by 6, that will give us 69)

x    =  69

The first number is x = 69

The second number is 2x = 2×69 =138

The third number is 3x = 3×69 =207

Adding all these numbers up will result to 414.

That is;

<em>69 + 138 + 207 =414</em>

<em></em>

Therefore the 2nd number is 138

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If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
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Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

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3. m<JKL = 10x - 11

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