Question

The sum of three consecutive numbers is 414. What is the 2nd number?

Answer 1

The equation for what the 2nd number of three consecutive numbers that equal to 414 is : x+(x+1)+(x+2)=414

Multiply and Simplify:

x+x+1+x+2=414

3x+3=414

Subtract 3 from both sides:

3x+3-3=414-3

3x=411

Divide three by both sides to get answer:

3x/3=411/3

x=137.

If you want to check if its correct add the three numbers that come next:

137+138+139=414.

Answer 2

Answer:  The 2nd number is 138

Step-by-step explanation:

Let x be the  first number, let 2x be the second number and let 3x be the third number

since the sum of the three consecutive numbers is 414, then this implies;

x + 2x + 3x =  414

6x            =    414

To get the value of x, we divide both-side of the equation by six(6)

6x / 6  =  414/6

(On the left-hand side of the equation, the six at the numerator will cancel out the six at the denominator leaving us with just x and the right-hand side of the equation, we will simply divide 414 by 6, that will give us 69)

x    =  69

The first number is x = 69

The second number is 2x = 2×69 =138

The third number is 3x = 3×69 =207

Adding all these numbers up will result to 414.

That is;

69 + 138 + 207 =414

Therefore the 2nd number is 138