All categories

3 years ago

Slope -5,y-intercept (0,3) What is f(x)

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

$f(x)=-5\ x+3$

Step-by-step explanation:

Given:

Slope of line =-5

y-intercept = $(0,3)$

The equation of line is given by :

$f(x)=m\ x+b$

where $m$ represents slope of line and $b$ represents y-intercept.

So from the given data, we have $m=-5$ and $b=3$

∴ The equation of line is given by:

$f(x)=-5\ x+3$

You might be interested in

What’s the equation for g(x)=<br><br> Please HELPPP I AM FAILING THIS

alukav5142 [94]

The function g represents y=x^2-3. The difference between function f and g is that g has a y intercept of -3

3 0

3 years ago

The expression 2m+ 10c gives the amount of money in dollars , a dessert store makes from selling m muffins and a c Cakes How muc

sveta [45]

Answer:

$46

Step-by-step explanation:

Given that :

The expression : 2m+ 10c ( amount made from selling muffins and C cakes.)

This means cost per muffin is 2 and cost per cake is 10

Hence, amount made from selling 3 muffins and 4 cakes ;

2(3) + 10(4)

$6 + $40

= $46

6 0

3 years ago

Suppose the germination periods, in days, for grass seed are normally distributed. If the population standard deviation is 3 day

KatRina [158]

Answer:

The minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean is 25.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

If the population standard deviation is 3 days, what minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean?

This is n when $\sigma = 3, M = 1$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$1 = 1.645*\frac{3}{\sqrt{n}}$

$\sqrt{n} = 3*1.645$

$(\sqrt{n})^{2} = (3*1.645)^{2}$

$n = 24.3$

Rouding up to the nearest integer, 25.

The minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean is 25.

4 0

3 years ago

Lawnco produces three grades of commercial fertilizers. A 100-lb bag of grade A fertilizer contains 18 lb of nitrogen, 4 lb of p

matrenka [14]

Answer:

We need to produce 600 100-lb bags of the grade A fertilizer

We need to produce 800 100-lb bags of the grade B fertilizer

We need to produce 500 100-lb bags of the grade C fertilizer

We need to produce 700 100-lb bags of the grade A fertilizer

We need to produce 850 100-lb bags of the grade B fertilizer

We need to produce 300 100-lb bags of the grade C fertilizer

Step-by-step explanation:

I am going to say that:

x is the number of 100-lb bags of grade A fertilizer

y is the number of 100-lb bags of grade B fertilizer

z is the number of 100-lb bags of grade C fertilizer

We have that:

A 100-lb bag of grade A fertilizer contains 18 lb of nitrogen, 4 lb of phosphate and 5 lb of potassium.

A 100-lb bag of grade B fertilizer contains 20 lb of nitrogen and 4 lb each of phosphate and potassium.

A 100-lb bag of grade C fertilizer contains 24 lb of nitrogen, 3 lb of phosphate, and 6 lb of potassium.

A) 38,800 lb of nitrogen, 7,100 lb of phosphate, and 9,200 lb of potassium are available and all the nutrients are used

This means that we have to solve the following system:

$18x + 20y + 24z = 38800$

$4x + 4y + 3z = 7100$

$5x + 4y + 6z = 9200$

In the second equation, i am going to write y as a function of x and z, and replacing of the the first and the third equation.

$4x + 4y + 3z = 7100$

$y = \frac{7100 - 4x - 3z}{4}$

In the first equation

$18x + 20\frac{7100 - 4x - 3z}{4} + 24z = 38800$

$18x + 5(7100 - 4x - 3x) + 24z = 38800$

$18x + 35500 - 20x - 15z + 24z = 38800$

$-2x + 9z = 3300$

In the third equation

$5x + 4\frac{7100 - 4x - 3z}{4} + 6z = 9200$

$5x + 7100 - 4x - 3z + 6z = 9200$

$x + 3z = 2100$

Now we have:

$-2x + 9z = 3300$

$x + 3z = 2100$

Now we multiply the second equation by 2, and add with the first:

$2x + 6z = 4200$

$-2x + 2x + 9z + 6z = 3300 + 4200$

$15z = 7500$

$z = 500$

We need to produce 500 100-lb bags of the grade C fertilizer

$x + 3z = 2100$

$x = 2100 - 3z = 600$

We need to produce 600 100-lb bags of the grade A fertilizer

$y = \frac{7100 - 4x - 3z}{4} = \frac{7100 - 4(600) - 3(500)}{4} = 800$

We need to produce 800 100-lb bags of the grade B fertilizer

B) 33,800 lb of nitrogen, 6,500 lb of phosphate, and 8,100 lb of potassium are available and all the nutrients are used

This means that we have to solve the following system:

$18x + 20y + 24z = 33800$

$4x + 4y + 3z = 6500$

$5x + 4y + 6z = 8100$

In the second equation, i am going to write y as a function of x and z, and replacing of the the first and the third equation.

$4x + 4y + 3z = 6500$

$y = \frac{6500 - 4x - 3z}{4}$

In the first equation

$18x + 20\frac{6500 - 4x - 3z}{4} + 24z = 33800$

$18x + 5(6500 - 4x - 3x) + 24z = 33800$

$18x + 32500 - 20x - 15z + 24z = 33800$

$-2x + 9z = 1300$

In the third equation

$5x + 4\frac{6500 - 4x - 3z}{4} + 6z = 8100$

$5x + 6500 - 4x - 3z + 6z = 8100$

$x + 3z = 1600$

Now we have:

$-2x + 9z = 1300$

$x + 3z = 1600$

Now we multiply the second equation by 2, and add with the first:

$2x + 6z = 4200$

$-2x + 2x + 9z + 6z = 1300 + 3200$

$15z = 4500$

$z = 300$

We need to produce 300 100-lb bags of the grade C fertilizer

$x + 3z = 1600$

$x = 1600 - 3z = 700$

We need to produce 700 100-lb bags of the grade A fertilizer

$y = \frac{6500- 4x - 3z}{4} = \frac{7100 - 4(700) - 3(300)}{4} = 850$

We need to produce 850 100-lb bags of the grade B fertilizer

7 0

3 years ago

Shau-uen solved the equation 18.5 w + 6.5 w minus 2.8 w = 149.1. Her work is shown below. Step 1 18.5 w + 6.5 w minus 2.8 w = 14

professor190 [17]

Answer: Step 3

Step-by-step explanation:

I just took the test

4 0

4 years ago

Read 2 more answers