-26/19 or -7 (if you just flip and simplify)
You would have to replace f(x) with zero and use quadratic formula
f(x)=x^2-5x+5
0=x^2-5x+5
=(-b+-√b^2-4ac)/2a
=(5+-√25-4(1)(5))/2
=(5+-√5)/2
x=(5+√5)/2 or x=(5-√5)/2
Both x values are completely applicable in the equation.
Hope I helped :)
Equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
In this case:
<span>center (2,7) and radius 4 so h = 2, k = 7 and r = 4
</span>Equation:
(x - 2)^2 + (y - 7)^2 = 4^2
(x - 2)^2 + (y - 7)^2 = 16
Hope it helps.
Factorization: (x + 4)∧2=0
Solutions based on Factorization: x + 4 = 0 ⇒ X∨1 = X∨2 = -4
Answer:
13/20
Step-by-step explanation: