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Lana71 [14]
3 years ago
6

the function Q(t)= Q(base o) e^(-kt) maybe be used to model radioactive decay. Q represents the quantity remaining after t years

; k is the decay constant, 0.00011. How long in years will it take for a quantity of plutonium-240 to decay to 25% of its original amount?
Mathematics
2 answers:
inysia [295]3 years ago
8 0

Answer: 12,600 years


Step-by-step explanation:


Tanzania [10]3 years ago
5 0
Half-Life = ln (.5) / k
Half-Life = .693147 / .00011
Half-Life = <span> <span> <span> 6,301 years

For a radioactive substance to decay to 25%, it has to go through 2 halflives.

2 * 6,301 = 12,602 years
approximately 12,600 years

</span></span></span>
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Theresa Morgan a chemist has a 10% hydrochloric acid solution and a 65% hydrochloric acid solution. How many liters of each shou
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<u>ANSWER: </u>

170 liters of 10% hydrochloric acid must be mixed with 1700 liters of 65% hydrochloric acid solution to obtain 1870 liters of 60% solution.

<u>SOLUTION: </u>

First, set up a table. Fill in the unknowns with variables x and y. The table is attached below

From this, we can easily set up the two equations.  

Sum of values of two acids = Value of mixture  

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For convenience, we'll multiply the entire equation by 100,

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multiply (2) with 10 for easy calculation and derive the equation into one variable.

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Subtracting equation (2) from (1),  

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