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LekaFEV [45]
3 years ago
15

SOLVE. y''+5y'+6y=2e^t

Mathematics
1 answer:
Stels [109]3 years ago
8 0
<span>y'' + 5y' + 6y = 2e^t is a second order differential equation with solution y = Ae^mt + Be^nt + p(t); where m and n are the roots of the quadratic equation x^2 + 5x + 6 = 0, and p(t) is the particular solution.
x = -2 and x = -3

y = Ae^-2t + Be^-3t + p(t)

For the particular solution, Ke^t + 5Ke^t + 6Ke^t = 2e^t
12K = 2
K = 1/6

Therefore, solution is </span>
<span>y = Ae^-2t + Be^-3t + 1/6 e^t
</span>
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