The image of the car park showing the 2 angles is attached.
Answer:
Their lines are parallel.
Step-by-step explanation:
From the attached image, we can see that ∠1 and ∠2 form a pair of alternate exterior angles. Thus; ∠1 = ∠2.
Now since they are congruent, it means that their lines will be parallel.
Thus, we can conclude that their lines are parallel.
Answer:
D
Step-by-step explanation:
4x2=8
5x2=10
6x2=12
This answer is the closest to 12 but it doesn't go over 12, so this is less than or equal to 12
The length of BC is 4.674 m
<u>Explanation:</u>
Given:
Angle A = angle B = 90°
AD = 2.1 m
AB = 1.9 m
CD= 3.2 m
An image is inserted for the reference
According to the figure,
a is the base
b is the height
c is the hypotenuse
Using pythagoras theorm:
a² + b² = c²
a² + (1.9)² = (3.2)²
a² + 3.61 = 10.24
a² = 6.63
a = 2.574
BC = 2.1 + 2.574
BC = 4.674m
Therefore, the length of BC is 4.674 m
The answer is here. Hope I did help you.
9514 1404 393
Answer:
a) w(4w-15)
b) w²
c) w(4w -15) = w²
d) w = 5
e) 5 by 5
Step-by-step explanation:
a) If w is the width, and the length is 15 less than 4 times the width, then the length is 4w-15. The area is the product of length and width.
A = w(4w -15)
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b) If w is the side length, the area of the square is (also) the product of length and width:
A = w²
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c) Equating the expressions for area, we have ...
w(4w -15) = w²
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d) we can subtract the right side to get ...
4w² -15w -w² = 0
3w(w -5) = 0
This has solutions w=0 and w=5. Only the positive solution is sensible in this problem.
The side length of the square is 5 units.
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e) The rectangle is 5 units wide, and 4(5)-15 = 5 units long.
The rectangle and square have the same width and the same area, so the rectangle must be a square.
