Use the appropriate normal distribution to approximate the resulting binomial distributions. A convenience store owner claims th
1 answer:
Answer:
0.9256
Step-by-step explanation:
Given that a convenience store owner claims that 55% of the people buying from her store, on a certain day of the week, buy coffee during their visit
Let X be the number of customers who buy from her store, on a certain day of the week, buy coffee during their visit
X is Binomial (35, 0.55)
since each customer is independent of the other and there are two outcomes.
By approximation to normal we find that both np and nq are >5.
So X can be approximated to normal with mean = np = 19.25
and std dev =
Required probability = prob that fewer than 24 customers in the sample buy coffee during their visit on that certain day of the week
= (after effecting continuity correction)
= 0.9256
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where P=initial number of rabbits
t=time
d=time it takes to doulbe
ok, so 4 weeks is the doubling time so that is 4*7=28 days
we wawnt time=98
and oroiginal number of rabbits is 5 so
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days
Answer:
The correct option is D.
Step-by-step explanation:
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Option D is correct.