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Lady bird [3.3K]

3 years ago

11

Please answer this question fast in two minutes

1 answer:

makkiz [27]3 years ago

5 0

Answer:<cgb and <dge

Step-by-step explanation:supplementary angles add up to 180 and <cgb+<dge +<cgd=180 because they are angles on a straight line

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Which is the best approximation of the solutions to the system of equations graphed below?

Neko [114]

According to the direct inspection, we conclude that the best approximation of the two solutions to the system of <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

<h3>What is the solution of a nonlinear system formed by two quadratic equations?</h3>

Herein we have two parabolae, that is, polynomials of the form a · x² + b · x + c, that pass through each other twice according to the image attached to this question. We need to estimate the location of the points by visual inspection on the <em>Cartesian</em> plane.

According to the direct inspection, we conclude that the best approximation of the two solutions, that is, the point where the two parabolae intercepts each other, to the system of two <em>quadratic</em> equations are (x₁, y₁) = (- 1, 0) and (x₂, y₂) = (1, 2.5). (Correct choice: C)

To learn more on quadratic equations: brainly.com/question/17177510

#SPJ1

4 0

1 year ago

What is the slope of the line? <br><br> A. -5 <br><br> B. 1/5<br><br> C. 5 <br><br> D. -1/5

jeka57 [31]

Answer:

bag.

Step-by-step explanation:

gate66

8 0

3 years ago

What is the positive solution to the equation 0=⅓x²-3

sammy [17]

Add 3, multiply by 3, and take the positive square root.
3 = (1/3)x²
9 = x²
√9 = 3 = x

The positive solution to the equation is x = 3.

7 0

3 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

marishachu [46]

Answer:

Thus, the two root of the given quadratic equation $x^2-6=-x$ is 2 and -3 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2-6=-x$

This can be written as , $x^2+x-6=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = 1 , c = -6

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(1)\pm\sqrt{(1)^2-4\cdot 1 \cdot (-6)}}{2 \cdot 1}$

$\Rightarrow x=\frac{-1\pm\sqrt{25}}{2}$

$\Rightarrow x=\frac{-1\pm 5}{2}$

$\Rightarrow x_1=\frac{-1+5}{2}$ and $\Rightarrow x_2=\frac{-1-5}{2}$

$\Rightarrow x_1=\frac{4}{2}$ and $\Rightarrow x_2=\frac{-6}{2}$

$\Rightarrow x_1=2$ and $\Rightarrow x_2=-3$

Thus, the two root of the given quadratic equation $x^2-6=-x$ is 2 and -3 .

7 0

3 years ago

Read 2 more answers

The town of madison has a population of 25,000. The population is increasing by a factor of 1.12 each year. Write a function tha

GaryK [48]

<h3>The population P(t) at the end of year t is $P(t) = 25,000 \times (1.12)^t$ </h3>

Step-by-step explanation:

The initial population of town of Madison = 25,000

The rate at which the population is increasing = 1.12 times

So, the increase in population first year :

( the initial population) x $(1.12)^1$ = 1.12 x ( 25,000)

= 28,000

So, the population at the end of first year = 28,000

Similarly, the increase in population second year :

( the initial population) x (1.12)² = ( 25,000) x (1.12)²

= 31,360

So, the population at the end of second year =31,360

Now, to calculate the population in t years from now:

The population P(t) at the end of year t is

$P(t) = 25,000 \times (1.12)^t$

5 0

3 years ago