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natulia [17]
3 years ago
12

I need help please and thank you

Mathematics
1 answer:
kakasveta [241]3 years ago
4 0

Answer:

975

Step-by-step explanation:

13 times 15 times 5= 975

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Amy had homework for math,science,and history.she spent 1/3 of her time working on math and 1/4 of her time working on science.
Alja [10]
First we need to multiply to make the fractions have equal denominators so we can add/subtract.

math: 1/3 x 4/4=4/12
science: 1/4 x 3/3=3/12

Now we can find the time she spent on history (I assume this is what you are looking for)

Total time-math time<span>-science time=history time</span>
12/12-4/12-3/12
=5/12

Amy spent 5/12 of her time working on history.

8 0
3 years ago
Read 2 more answers
Which option equals tan 40°? Select all that apply.
Sonbull [250]
Answers:
(sin40)/(cos40) and
(cos50)/(sin50)
4 0
3 years ago
Plz plz somebody help me i will mark you has brainlest pls its due at 8:00 its like 7:43
Crazy boy [7]

Answer: She is incorrect because 0 + 0 = <u>0</u>

6 0
3 years ago
Solve using the quadratic formula<br><br> x^2-4x+1=0
sergiy2304 [10]

Answer:

x=2+ or - the square root of 3

Step-by-step explanation:

solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.

4 0
3 years ago
Read 2 more answers
Which of the following geometric series converges?
Artist 52 [7]

All three series converge, so the answer is D.

The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.

Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

S_n=a+ar+ar^2+\cdots+ar^{n-2}+ar^{n-1}

Multiply both sides by <em>r</em> :

rS_n=ar+ar^2+ar^3+\cdots+ar^{n-1}+ar^n

Subtract the latter sum from the first, which eliminates all but the first and last terms:

S_n-rS_n=a-ar^n

Solve for S_n:

(1-r)S_n=a(1-r^n)\implies S_n=\dfrac a{1-r}-\dfrac{ar^n}{1-r}

Then as gets arbitrarily large, the term r^n will converge to 0, leaving us with

S=\displaystyle\lim_{n\to\infty}S_n=\frac a{1-r}

So the given series converge to

(I) -243/(1 + 1/9) = -2187/10

(II) -1.1/(1 + 1/10) = -1

(III) 27/(1 + 1/3) = 18

8 0
3 years ago
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