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Fudgin [204]
4 years ago
7

The displacement, d, in millimeters of a tuning fork as a function of time, t, in seconds can be modeled with the equation d = 0

.6 sin (3520rt) . What is the frequency of the tuning fork?A,1/3520 Hz B. 1/1760 Hz C. 1760 Hz D. 3520 Hz
Mathematics
2 answers:
blagie [28]4 years ago
4 0

Answer:

C is correct. 1760 Hz

Step-by-step explanation:

The displacement (d) in millimeters of a tuning fork as a function of time t

d=0.6\sin(3520\pi t)

If we compare with wave equation

y=a\sin(\omega t)

If we compare it with our equation we get

\omega=3520\pi

As we know the formula of \omega=2\pi \nu

\therefore 2\pi \nu=3520\pi

\nu=1760\text{ Hz}

Thus, The frequency of the tuning fork is 1760 Hz

xenn [34]4 years ago
4 0
It's C. 1760hz.  I took the exam on the website.
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