Question

The displacement, d, in millimeters of a tuning fork as a function of time, t, in seconds can be modeled with the equation d = 0.6 sin (3520rt) . What is the frequency of the tuning fork?A,1/3520 Hz B. 1/1760 Hz C. 1760 Hz D. 3520 Hz

Answer 1

Answer:

C is correct. 1760 Hz

Step-by-step explanation:

The displacement (d) in millimeters of a tuning fork as a function of time t

$d=0.6\sin(3520\pi t)$

If we compare with wave equation

$y=a\sin(\omega t)$

If we compare it with our equation we get

$\omega=3520\pi$

As we know the formula of $\omega=2\pi \nu$

$\therefore 2\pi \nu=3520\pi$

$\nu=1760\text{ Hz}$

Thus, The frequency of the tuning fork is 1760 Hz

Answer 2

It's C. 1760hz.  I took the exam on the website.