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Ivanshal [37]
3 years ago
12

HELP PLEASE!

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0
Answer: y = 5*(7/5)^x
Note: In decimal form, the equation is y = 5*(1.4)^x because 7/5 = 1.4

--------------------------------------------------------------------------

Explanation:

The general exponential form is y = a*b^x
Plug in the first point (x,y) = (0,5) and we can find 'a' to be...
y = a*b^x
5 = a*b^0
5 = a*1
5 = a
a = 5

Which means y = a*b^x updates to y = 5*b^x
Now plug in the other point (x,y) = (1,7) to find b
y = 5*b^x
7 = 5*b^1
7 = 5*b
b = 7/5
b = 1.4

So the equation is y = 5*(7/5)^x which is equivalent to y = 5*(1.4)^x

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Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

a_{1}=1

a_{n}=a_{n-1}+3

General term of the arithmetic sequence.

a_{n}=a_{n-1}+d, where d is the common difference.

d = 3

a_{n}=a_{n-1}+3

Put n = 2 in a_{n}=a_{n-1}+3, we get

a_{2}=a_1+3

a_{2}=1+3

a_2=4

Put n = 3 in a_{n}=a_{n-1}+3, we get

a_{3}=a_2+3

a_{3}=4+3

a_3=7

Put n = 4 in a_{n}=a_{n-1}+3, we get

a_{4}=a_3+3

a_{4}=7+3

a_4=10

Put n = 5 in a_{n}=a_{n-1}+3, we get

a_{5}=a_4+3

a_{5}=10+3

a_5=13

The first five terms of the sequence are 1, 4, 7, 10, 13.

3 0
3 years ago
a square dance set requires 4 couples 8 dancers with each couple standing on one side of a square. There are 250 people at a squ
sveta [45]

Given:

1 set requires 4 couples 8 dancers.

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\text{Number of possible sets}=\dfrac{250}{8}

\text{Number of possible sets}=31.25

Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

\text{Number of possible sets}\approx 31

Therefore, the number of possible sets at the dance is 31.

7 0
2 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

3x-4(4)=65

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3x=65-16

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