The first five terms of the sequence are 1, 4, 7, 10, 13.
Solution:
Given data:


General term of the arithmetic sequence.
, where d is the common difference.
d = 3

Put n = 2 in
, we get



Put n = 3 in
, we get



Put n = 4 in
, we get



Put n = 5 in
, we get



The first five terms of the sequence are 1, 4, 7, 10, 13.
Given:
1 set requires 4 couples 8 dancers.
Total number of people at a square dance = 250.
To find:
The greatest number of sets possible at the dance.
Solution:
We have,
Total people = 250
1 set = 8 people.



Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.

Therefore, the number of possible sets at the dance is 31.
3, 6, 12
I guessed and checked. So if 3 is the smallest number, I would, multiply it by 3, which is 9. 9 is 3 less than the largest number which would be 12. 12 + 3 is 15. To find the third number, subtract 21 and 15 which is 6
Answer:
16.3 repeating
Step-by-step explanation:
3x-4(4)=65
3x-16=65
3x=65-16
3x=49
x=49/3
x=16.3 repeating
18 Kids in his class you have to divide 72 by 4 which will give u 18
Good Luck! ~Sophie Hernandez