Answer:
36. There are 36 students in the class.
Step-by-step explanation:
4/12 oatmeal
2/12 cinnamon
3/12 chocolate
9 peanut
The fractions added together = 9/12
This means the 9 students = 3/12 of the class
3 x 4 = 12
9 x 4 = 36
Solution :
Let A = Economics, B = Mathematics
n(A) = 311, n(B) = 243, 
a). So, 
= 311 + 243 - 135
= 419
b). n(A only) = 311 - 135
= 176
n(B only) = 243 - 135
= 108
Exactly one of these two courses
= 0.568
c). Neither economics nor mathematics
= 0.162
50% or 1/2 of 4 is 2 50% or 1/2 of 6 is 3 so then just add them to the respective number since its going up by 50% or 2 in by 3 in \[\frac{ 6 }{ 9}\]
Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
Es 44. Esta página está en inglés, entonces nadie te va a responder la pregunta D=. Deberían de hacer una versión en español de esta página.
