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mezya [45]
2 years ago
9

PLEASE HELP ILL MAKE YOU THE BRAINIEST Find the value of x

Mathematics
1 answer:
Firdavs [7]2 years ago
4 0

Answer:

12.04

Step-by-step explanation:

add 8 and 9 by the power of two: 8^2+9^2

that equals to 145

find the square root of 145 and that equals to 12.04

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Select the correct answer. what is this expression in simplified form? (6v2)(-3v5)
Roman55 [17]

Answer:

-180v^2

Step-by-step explanation:

multiply and calculate

3 0
2 years ago
Alicia has invented a new app that two companies are interested in purchasing for a 2-year contract. Company A is offering $10,0
Fantom [35]

Answer:

Month 8

In this month Company B's plan will pay $64,000 versus $45,000 from Company A.

Step-by-step explanation:

Start by calculating the monthly payments for both plans.

Month - Company A - Company B

1      $10,000        $500

2      $15,000       $1,000

3      $20,000       $2,000

4      $25,000       $4,000

5      $30,000       $8,000

6      $35,000       $16,000

7      $40,000      $32,000

8      $45,000      $64,000

9      $50,000     $128,000

10      $55,000     $256,000

11 $60,000 $512,000

12 $65,000 $1,024,000

13 $70,000 $2,048,000

14 $75,000 $4,096,000

15 $80,000 $8,192,000

16 $85,000 $16,384,000

17 $90,000 $32,768,000

18 $95,000 $65,536,000

19 $100,000 $131,072,000

20 $105,000 $262,144,000

21 $110,000 $524,288,000

22 $115,000 $1,048,576,000

23 $120,000 $2,097,152,000

24 $125,000 $4,194,304,000


7 0
4 years ago
Read 2 more answers
There are 3 consecutive numbers whose sum is equal to the result of their multiplication. Which are they?
OleMash [197]
They are 1, 2 and 3.

Hope that helped ^^
7 0
3 years ago
A manufacturing company with 450 employees begins a new product line and must increase their number of employees by 18% how many
Artemon [7]
The company will have a total number of 531 employees
5 0
3 years ago
34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
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