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Levart [38]
3 years ago
7

For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth

er the graph displays the behavior of a touch or a cross at each intercept.
Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

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Answer: the value of the car in 2019 is $5269

Step-by-step explanation:

It loses 12% of its value every year. This means that the value of the car is decaying exponentially. We would apply the formula for exponential decay which is expressed as

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A represents the value of the car after t years.

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From the information given,

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2 years ago
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Romashka-Z-Leto [24]

∛(-45) = ∛((-1) × 45) = ∛(-1) × ∛45 = -∛45

Similarly,

∛(-101) = - ∛101

Now,

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So to summarize, we have

3 < ∛45 < 4 < ∛101 < 5

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3 years ago
((2)/(3))+((3)/(2))
olya-2409 [2.1K]
  • Answer:

<em>13/6</em>

<em>2  1/6</em>

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<em>²⁾2/3 + ³⁾3/2 = </em>

<em>= 4/6 + 9/6</em>

<em>= (4 + 9)/6</em>

<em>= 13/6</em>

<em>= 2  1/6</em>

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