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Levart [38]
3 years ago
7

For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth

er the graph displays the behavior of a touch or a cross at each intercept.
Mathematics
1 answer:
murzikaleks [220]3 years ago
7 0

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

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lakkis [162]

Answer:

\frac{x}{3}  + 4 =  \frac{4x - 1}{5}  \\  \\  \frac{x}{3}  +  \frac{12}{3}  =  \frac{4x - 1}{5}  \\  \\  \frac{x + 12}{3}  =  \frac{4x - 1}{5}  \\  \\ 3(4x - 1) = 5(x + 12) \\  \\ 12x - 3 = 5x + 60 \\  \\ 12x - 5x = 60 + 3 \\  \\ 7x = 63 \\  \\ x =  \frac{63}{7}  \\  \\ x = 9

7 0
2 years ago
Please don't give me a FILE<br> PLEASE HELPPP ILL GIVE 15 POINTS AND BRAINLIST
pickupchik [31]

Answer:

3/2

Step-by-step explanation:

My reasoning is that the sum of the numbers in the left is equal to the sum of the numbers in the right.

Therefore 6=2y+3

2y=6-3

2y=3

y=1.5 or 1and a half which is equivalent to 3/2

4 0
3 years ago
Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.
Anika [276]
For this case we have the following functions:
 h (x) = 2x - 5
 t (x) = 6x + 4

 Part A: (h + t) (x)
 (h + t) (x) = h (x) + t (x)
 (h + t) (x) = (2x - 5) + (6x + 4)
 (h + t) (x) = 8x - 1

 Part B: (h ⋅ t) (x)
 (h ⋅ t) (x) = h (x) * t (x)
 (h ⋅ t) (x) = (2x - 5) * (6x + 4)
 (h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
 (h ⋅ t) (x) = 12x ^ 2 - 22x - 20

 Part C: h [t (x)]
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6 0
3 years ago
Let f(X)=3√x
SOVA2 [1]

g(x) = 3√(x-5) -1

The process of altering a graph to produce a different version of the preceding graph is known as graph transformation. The graphs can be moved about the x-y plane or translated. They may also be stretched, or they may undergo a mix of these changes.

Horizontal stretching: It means the graph is elongated or shrink in x direction.

Vertical stretching : It means the graph is elongated or shrink in y direction

Vertical translation : It means moving the base of the graph in y direction

Horizontal translation : It means moving the base of the graph in x direction

According to rules of transformation f(x)+c shift c units up and f(x)-c shift c units down.

Therefore, in order to  move the graph down 1 units, we need to subtract given function by 1 , we get

g(x) = 3√x -1

According to rules of transformation f(x+c) shift c units left and f(x-c ) shift c units right.

Therefore, in order to  move the graph left by 5 units, we need to add given function by 5 , we get

g(x) = 3√(x-5) -1

To learn more about graphical transformation,  refer to brainly.com/question/4025726

#SPJ9

4 0
1 year ago
F(x) = x2 + 1<br> g(x) = 5-x<br> (f+g)(x) =<br> O x2 + x-4<br> x²+x+4<br> O x2-x+6<br> O x2 + x + 6
charle [14.2K]

Answer:

\boxed{(f + g)(x) = {x}^{2} - x + 6}

Given:

f(x) =  {x}^{2}  + 1 \\  \\ g(x) = 5 - x

To Find:

(f + g)(x) = f(x) + g(x)

Step-by-step explanation:

=  > f(x) + g(x) =  ({x}^{2}  + 1) + (5 - x) \\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2}  + 1 + 5 - x\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2}  + 6 - x\\  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = {x}^{2} - x + 6

5 0
3 years ago
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