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3 years ago

What is the equivalent expression in factored form of 15x^7y^2+4x^3

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

4 0

Answer:

x^3(15x^4y^2+4)

Step-by-step explanation:

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stephen and bridget win some money and share it in the ratio 5:2. stephen gets £65. how much does bridget get

katen-ka-za [31]

Answer:

Bridget will get the amount as £26.

Step-by-step explanation:

Given:

Amount Stephen gets = £65

Amount shared in ratio = 5:2

We need to find the amount Bridget gets.

Solution:

Let the common factor in the ratio be $'x'$ .

Amount Stephen gets = $5x$

Amount Bridget gets = $2x$

But we know that;

Amount Stephen gets = £65

so we can say that;

$5x=65$

Now dividing both side by 5 we get;

$\frac{5x}{5}=\frac{65}{5}\\\\x=13$

So now we get;

Amount Bridget gets = $2x=2\times 13 = \£26$

Hence Bridget will get the amount as £26.

3 0

3 years ago

Cameron needs to order some new supplies for the restaurant where he works. The

zvonat [6]

Answer:

598=194+8x

Step-by-step explanation:

To solve you would subtract 194 from its self and 598

598=194+8x

-194 -194

404=8x

then you would divide 8 from it's self and 404

which would make it 50.5

(but you cant buy half a package of spoons so realistically it'd be 50 or 51.

hope this helped :)

6 0

2 years ago

Read 2 more answers

A jar contains 25 coins of only dimes and quarters. The value of the jar is $4.45. Write the equation that represent the money v

8_murik_8 [283]

Answer:

Step-by-step explanation:

3 0

2 years ago

Please tell me the final answer and how you got it.

dem82 [27]

It is 484 m^2 ,to my understanding!

5 0

3 years ago

When and how do you use logarithms to solve exponential equations? give an example of an exponential equation that does not requ

tatuchka [14]

$\bf 5^{x+3}=\cfrac{1}{125}\implies 5^{x+3}=\cfrac{1}{5^3}\implies 5^{x+3}=5^{-3}
\\\\\\
\textit{because the bases are the same, the exponents must also be the same}
\\\\\\
x+3=-3\implies \boxed{x=-6}\\\\
-------------------------------\\\\
3^x=4^{2x}\implies log(3^x)=log(4^{2x})\implies xlog(3)=(2x)log(4)
\\\\\\
\cfrac{x}{2x}=\cfrac{log(4)}{log(3)}\implies \cfrac{1}{x}=\cfrac{log(4)}{log(3)}\implies \cfrac{log(3)}{log(4)}=x\implies \boxed{0.79248125\approx x}$

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3 years ago