You are correct! The problems that can arise with a function domain are:
- Denominators that become zero
- Even-degree roots with negative input
- Logarithms with negative or zero input
In this case, you have a denominator, and you don't have roots nor logarithms. This means that your only concern must be the denominator, specifically, it cannot be zero.
And you simply have
So, the domain of this function includes every number except 3.
Answer:
The function of g(x) = 5x + 2
Step-by-step explanation:
Let us use the composite function to solve the question
∵ f(x) = 2x - 1
∵ f(g(x)) = 10x + 3
→ f(g(x)) means substitute x in f(x) by g(x)
∴ f(g(x)) = 2[g(x)] - 1
→ Equate the two right sides of f(g(x))
∴ 2[g(x)] - 1 = 10x + 3
→ Add 1 to both sides
∴ 2[g(x)] - 1 + 1 = 10x + 3 + 1
∴ 2[g(x)] = 10x + 4
→ Divide each term into both sides by 2
∵ ![\frac{2[g(x)]}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Bg%28x%29%5D%7D%7B2%7D)
= 
+ 
∴ g(x) = 5x + 2
∴ The function of g(x) = 5x + 2
Answer:
10.2 cm
Step-by-step explanation:
Divide the tail length by 10
HoPe ThIs HeLpEd youuu! lol :)
Answer: 3/5
Step-by-step explanation: thats your answer.
Answer:
24/35
Step-by-step explanation:
