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Lilit [14]
3 years ago
10

Determine whether the data shows a linear relationship. If so, write an equation of a line of it.

Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

  • The data do not show a linear relationship

Step-by-step explanation:

A plot of the points connected by straight lines makes it pretty clear they do not all fall on the same line. There is no linear relationship here.

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the vertex of this parabola is at (-2,-3). When the x. value is -1and the y value is -5, what is the coefficient of the squared
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Rewrite the function f(x)=-4(x-3)^2+16 in the form f(x)=ax^2+bx+c
elena55 [62]

Answer:

f(x) = - 4x² + 24x - 20

Step-by-step explanation:

Given

f(x) = - 4(x - 3)² + 16 ← expand the factor using FOIL

     = - 4(x² - 6x + 9) + 16 ← distribute parenthesis by - 4

    = - 4x² + 24x - 36 + 16 ← collect like terms

    = - 4x² + 24x - 20

4 0
2 years ago
Find an equation for the line that passes through the points (5.-5) and (-4,-2)
ANEK [815]

Answer:

\large\boxed{y=-\dfrac{1}{3}x-\dfrac{10}{3}\to x+3y=-10}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (5, -5) and (-4, -2).

Substiute:

m=\dfrac{-2-(-5)}{-4-5}=\dfrac{-2+5}{-9}=\dfrac{3}{-9}=-\dfrac{1}{3}

Put the value of the slope and the coordinates of the point (5, -5) to the equation of a line:

-5=-\dfrac{1}{3}(5)+b

-5=-\dfrac{5}{3}+b               <em>add 5/3 to both sides</em>

-\dfrac{15}{3}+\dfrac{5}{3}=b\\\\-\dfrac{10}{3}=b\to b=-\dfrac{10}{3}

Finally we have the equation of a line in the slope-intercept form:

y=-\dfrac{1}{3}x-\dfrac{10}{3}

Convert to the standard form <em>(Ax + By = C)</em>:

y=-\dfrac{1}{3}x-\dfrac{10}{3}          <em>multiply both sides by 3</em>

3y=-x-10              <em>add x to both sides</em>

x+3y=-10

4 0
3 years ago
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