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11Alexandr11 [23.1K]
2 years ago
12

27a+1/2b=4 solve for a

Mathematics
2 answers:
sladkih [1.3K]2 years ago
5 0

Answer:

a = 4/27 - b/54

Step-by-step explanation:

27a+1/2b=4

Subtract 1/2 b from each side

27a+1/2b - 1/2 b=4-1/2 b

27a = 4 - 1/2 b

Divide each side by 27

27a/27 = 4/27 - 1/2 b/27

a = 4/27 - b/54

GarryVolchara [31]2 years ago
5 0
Answer: a= - 1/54b+4/27

Step-by-step explanation:
primero multiplique ambos lados de la ecuación por 2
54a+b=8
mueve la variable al lado derecho y cambie su signo
54a=8-b
dividí ambos lados de la ecuación entre 54
a=4/27 - 1/54b
use la propiedad conmutativa para reorganizar los términos
a= 1/54b + 4/27 y listo
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Answer:

-4

Step-by-step explanation:

-129 = 6(7 + 7x) - 3

Distribute the 6 into the parentheses.

-129 = 42 + 42x - 3

Add like terms.

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Subtract 39 from both sides.

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Divide 42 from both sides.

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7 0
3 years ago
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Simplify the expression below.
Degger [83]

Answer:

6x^2 +8x

Step-by-step explanation:

(12x^3 -14x^2 -40x) / (2x-5)

Factor the numerator by factoring out the greatest common factor

2x( 6x^2 -7x-20) / (2x-5)

Factor inside the parentheses

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6 0
2 years ago
6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the
shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

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2 years ago
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PQR is an isosceles triangle in which PQ = PR
otez555 [7]

Answer and Step-by-step explanation: Congruent triangles are triangles with the same three sides and same three angles.

There many ways to determine if 2 triangles are congruent.

One of them is <u>ASA</u> or <u>Angle, Side, Angle</u> and it means that if two angles and the included side of one triangle are equal to the corresponding angles and side on the other triangle, they are congruent.

In this case, angle MRQ and angle NQR are equal. The included side of both triangles are the same QR, so it can be concluded that <em><u>triangle QNR is congruent to triangle RMQ.</u></em>

The image in the attachment shows the angles and their included side, which are colored.

3 0
3 years ago
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