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tiny-mole [99]
3 years ago
10

PLZ HELP! MATH

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0
The third one I think
NNADVOKAT [17]3 years ago
3 0

the answer is a dilation and a rotation because the rotation will make it stand u in the same way as the the other one and the dilation will make it bigger


HOPE THIS HELPS : )

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Evgesh-ka [11]

Answer:

this is school work

Step-by-step explanation: sorry but you gotta figure this out yourself.

but, the thing is that you should figure out the stuff inside the (these -->) then figure out the rest step by step like this, x= what then try to understand y= what, then use them to answer the problem.

and if its like this 1(4x + 5y) that mean that 9xy times 1 is your answer, this is an example.

8 0
3 years ago
Can you prove that def=hgf? Justify your answer.
stellarik [79]
The image is needed so I can work this out
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3 years ago
An agency is studying the income of store managers in the retail industry. A random sample of 25 managers reveals a sample mean
aalyn [17]

Answer:

The Confidence Interval = ($44,745.55 , $46,094.45)

Step-by-step explanation:

The formula for Confidence Interval =

Confidence Interval = Mean ± z × Standard deviation/√n

Where n = number of samples = 25 managers

Standard deviation = $2,050

Mean = $45,420

z = z score of the given confidence interval

= z score of 90% confidence interval

= 1.645

Confidence Interval = $45,420 ± 1.645 × $2,050/√25

= $45,420 ± 1.645 × $2,050/5

= $45,420 ± 674.45

Confidence Interval =

$45,420 - 674.45 = $44,745.55

$45,420 + 674.45 = $46,094.45

Therefore, the Confidence Interval = ($44,745.55 , $46,094.45)

3 0
3 years ago
We know that y=mx+b is the formula we use for lines. Is the value of "m" considered to be a term, a coefficient or a factor?
trapecia [35]
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4 0
3 years ago
is picking out some movies to rent, and he has narrowed down his selections to 5 documentaries, 7 comedies, 4 mysteries, and 5 h
pogonyaev

Answer: 91

Step-by-step explanation:

Given : The number of documentaries = 5

The number of comedies = 7

The number of mysteries = 4

The number of horror films =5

The total number of movies other than comedy = 14

Now, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is given by :-

^7C_7\times^{14}C_2\\\\\dfrac{7!}{7!(7-7)!}\times\dfrac{14!}{2!(14-2)!}\\\\=(1)\times\dfrac{14\times13}{2}\\\\=91

Therefore, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is 91 .

5 0
3 years ago
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