Considering the angle a by cosine rule
11^2 =7 ^2 +15^2 - 2(7)(15)cos(a)
When you do the maths,
Cos(a) =153/210 =0.729
a= cos inverse of 0.729
a=43 degrees
Considering angle b
7^2=15^2 +11^2 -2(11)(15) cos(b)
This will result in cos(b) =297/330=0.9
b= cos inverse of 0.9 = 25.8 degrees
Considering angle c
15^2=7^2 +11^2 - 2(11)(7) cos(c)
Cos(c) will be = -55/154 = -0.357
c= cos inverse of -0.357=110.9
Comparing the angles a,b and c,
C is the largest size in the triangle with an angle of 110.9 degrees
Am I right please ??
It would be easier to translate this into mathematical terms first.
Let n = the unknown number
6n <span>> n + 20
Subtracting both sides by n to simplify:
6n - n </span><span>> n + 20 - n
</span>5n <span>> 20
</span><span>
Dividing both sides by 5:
5n/5 </span><span>> 20/5
</span>n <span>> 4
</span><span>
Among the choices, the correct one is the second choice.
</span>
Answer:
9.5 ft^2
Step-by-step explanation:
It’s just 4.75 * 2
The answer is B. slope 0 intercept -5
