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3 years ago

I need help with this somebody help

Mathematics

1 answer:

Mariulka [41]3 years ago

3 0

Answer:

Width: x + 3

(Length, width):

(5,4) (6,5) (7,6)

Step-by-step explanation:

x² + 7x + 12

x² + 4x + 3x + 12

x(x + 4) + 3(x + 4)

(x + 4)(x + 3)

Longer one is the length,

With is (x + 3)

x = 1,

5 × 4

x = 2,

6 × 5

x = 3,

7 × 6

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What is the contrapositive of the statement below?

algol13

Answer:

B. -y = -x

Step-by-step explanation:

When the values on both sides of the equal sign are changed, it becomes a negative number.

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3 years ago

What is the value of i 97 – i? –i 0 –2i i Superscript 96

Valentin [98]

The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue

Answer:

$i^{97}-i=0$

Step-by-step explanation:

Powers of The Imaginary Unit

The imaginary unit i is defined as

$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

$i^2=(\sqrt{-1})^2=-1$

$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

The given expression is

$i^{97}-i$

Factoring

$i(i^{96}-1)$

Since $i^{96}=1$

$=i(1-1)=0$

The required value is 0

6 0

3 years ago

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A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple

devlian [24]

Answer:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=46$ represent the mean height for the sample

$s=5.148$ represent the sample standard deviation

$n=5$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:

Null hypothesis: $\mu = 40$

Alternative hypothesis: $\mu \neq 40$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606$

The degrees of freedom are given by:

$df=n-1=5-1=4$

The p value wuld be given by:

$p_v =2*P(t_{(4)}>2.606)=0.060$

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

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4 years ago

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Blababa [14]

Answer:

1. 216.8 N

2.328.635 N

3. 405.153 N

4. 580.752 N

5. 765.18 N

Step-by-step explanation:

1. Let the mass is 22.1 kg, then the weight in Newton will be (22.1 × 9.81) = 216.8 N {Where acceleration due to gravity is 9.81 m/sec²}

2. Let the mass is 33.5 kg, then the weight in Newton will be (33.5 × 9.81) = 328.635 N {Where acceleration due to gravity is 9.81 m/sec²}

3. Let the mass is 41.3 kg, then the weight in Newton will be (41.3 × 9.81) = 405.153 N {Where acceleration due to gravity is 9.81 m/sec²}

4. Let the mass is 59.2 kg, then the weight in Newton will be (59.2 × 9.81) = 580.752 N {Where acceleration due to gravity is 9.81 m/sec²}

5. Let the mass is 78 kg, then the weight in Newton will be (78 × 9.81) = 765.18 N {Where acceleration due to gravity is 9.81 m/sec²}

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3 years ago

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Answer:

Step-by-step explanation:

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