Answer:
x ∈ {-a, -b}
Step-by-step explanation:
1/(a+b+x) = 1/a +1/b +1/x . . . . given
abx = bx(a+b+x) +ax(a+b+x) +ab(a+b+x) . . . . multiply by abx(a+b+x)
(a+b)x^2 +(a+b)^2x +ab(a+b) = 0 . . . . . subtract abx
x^2 + (a+b)x +ab = 0 . . . . . divide by (a+b)
This is a quadratic equation in x. It will have two solutions, as given by the quadratic formula.
x = (-(a+b) ±√((a+b)^2 -4(1)(ab))/(2(1)) = (-(a+b) ± |a -b|)/2
Without loss of generality, we can assume a ≥ b, so |a -b| ≥ 0. Then ...
x = (-a -b -a +b)/2 = -a
x = (-a -b +a -b)/2 = -b
There are two solutions: x ∈ {-a, -b}.
Answer:
Segment DE is parallel to segment BC.
Step-by-step explanation:
Use the side splitter theorem.
Answer: Segment DE is parallel to segment BC.
Answer:
with what my g ????
Step-by-step explanation:
The correct answer is that g(-1) = 1.
To do this problem, we have to plug in -1 for x and evaluate the expression.
g(-1) = x^3 + 6x^2 + 12x + 8
(-1)^3 + 6(-1)^2 + 12(-1) + 8
-1 + 6 -12 + 8
1
(X - 3) to the second power( it won’t let me add a 2 by the parentheses
