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expeople1 [14]
3 years ago
9

Verify that sin (π + q) = -sin q is an identity.

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0
Bearing in mind that cos(π) is -1, and sin(π) is 0, then

\bf \textit{Sum and Difference Identities}
\\\\
sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta)\\\\
-------------------------------\\\\
sin(\pi +q)=sin(\pi )cos(q)+cos(\pi )sin(q)
\\\\\\
sin(\pi +q)=0\cdot  cos(q)+(-1)\cdot sin(q)\implies sin(\pi +q)=-sin(q)
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The formula for the circumference of a circle is c-nd, where d is the length of the diameter. If d is a rational number, what ca
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Answer:

could you add a pi

Step-by-step explanation:

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3 years ago
Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (
Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(c) (1, 0), (2, 0), (1, 3), (4, 3), (5, 7)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0
3 years ago
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What are the 2 greatest common factors of 32?
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Two common factors of 32 are: 8 and 4
4 0
4 years ago
Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of
zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

S = \theta r

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}

The arc length of the smaller gear is:

\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7

\displaystyle S_1=\frac{18.5\pi}{3}

The larger gear rotates the same arc length, so:

\displaystyle S_2=\frac{18.5\pi}{3}

\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}

Solving for θ2:

\displaystyle \theta_2=\frac{18.5\pi}{3r_2}

\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}

\theta_2=2.73\ radians

\displaystyle \theta_2=2.73*\frac{180}{\pi}=156

The larger gear will rotate through 156°

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