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Scorpion4ik [409]
3 years ago
6

What is the answer to this question

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0
1.20/4 = 0.3

Hope this helps!

Please mark me as brainliest if you can, I really appreciate it!
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A company that manufactures toy trains is making a new boxcar. To fit on the track, the smallest dimension of the toy boxcar mus
pochemuha

Answer:

Length = 12 inches, height = 3 inches

Step-by-step explanation:

First, you have to set up a proportion. 2/7, x/42.

Then, you cross multiply and get the setup of 84=7x

Finally, you divide 84 by 7 and get 12.

12 is the length, and there is no other answer that has 12 in the height. You could just do the same proportion to get 3, though.

8 0
3 years ago
Read 2 more answers
What is the triangle's base, b?
Oksi-84 [34.3K]

Answer:

6.928 or 6.93

Step-by-step explanation:

\sqrt{8^{2}-4^{2}}

4 0
3 years ago
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64.8=6(m+2.9) <br> what is m<br> please help me and explain how did you get your answer
BabaBlast [244]

Answer:

= −11.2

Step-by-step explanation:

64.8=6(m+22)

We move all terms to the left:

64.8-(6(m+22))=0

We calculate terms in parentheses: -(6(m+22)), so:

6(m+22)

We multiply parentheses

6m+132

Back to the equation:

-(6m+132)

We get rid of parentheses

-6m-132+64.8=0

We add all the numbers together, and all the variables

-6m-67.2=0

We move all terms containing m to the left, all other terms to the right

-6m=67.2

4 0
3 years ago
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The horsepower , H(s), required for a racecar to overcome wind resistance is given by the function : H(s) = 0.003s^2+0.07s-0.027
mote1985 [20]
Average rate of change = [H(100) - H(80)] / (100 - 80)
H(100) = 0.003(100)^2 + 0.07(100) - 0.027 = 0.003(10000) + 0.07(100) - 0.027 = 30 + 7 - 0.027 = 36.973

H(80) = 0.003(80)^2 + 0.07(80) - 0.027 = 0.003(6400) + 0.07(80) - 0.027 = 19.2 + 5.6 - 0.027 = 24.773

Average rate of change = (36.973 - 24.773)/(100 - 80) = 12.2/20 = 0.61

Answer: B
8 0
3 years ago
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5.35/46= ? i hate my mah class cane someone help me
KatRina [158]

Answer:

0.7

Step-by-step explanation:

Glad to help :)

7 0
2 years ago
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