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MrRa [10]
3 years ago
12

PLS HELPPP I don’t understand and I need help if so pls pls

Mathematics
2 answers:
lisov135 [29]3 years ago
6 0
Yeah he’s exactly right...... A
Anuta_ua [19.1K]3 years ago
5 0

Answer:

A

Step-by-step explanation:

rod is closest at 3m change

judy is medium at 7 m change

nelda is deepest at 9m change

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A cone is placed inside a cylinder. The cone has half the radius of the cylinder, but the height of each figure is the same. The
Feliz [49]

Answer:

\frac{11}{12}\pi r^{2}h\ units^{3}

Step-by-step explanation:

we know that

<em>Te volume of the cone is equal to</em>

V=\frac{1}{3}\pi r^{2}h

we have

r=(r/2)\ units

substitute

V=\frac{1}{3}\pi (r/2)^{2}h

V=\frac{1}{12}\pi r^{2}h

<em>Te volume of the cylinder is equal to</em>

V=\pi r^{2}h

we know that

To find the volume of the space remaining in the cylinder after the cone is placed inside it, subtract the volume of the cone from the volume of cylinder

so

\pi r^{2}h-\frac{1}{12}\pi r^{2}h=\frac{11}{12}\pi r^{2}h\ units^{3}

5 0
3 years ago
Three times a number is six. What is the number ?
IrinaK [193]
2. Because 3 x 2 = 6
3 0
3 years ago
Read 2 more answers
Pls write answer as soon as possible
Tomtit [17]

Answer:

Step-by-step explanation:

11.-3(2x-8)=-12

-6x+24=-12

-6x=-12-24

x=-36/-6

x=6

12.4(6+2x)=0

24+8x=0

8x=0-24

x=-24/8

x=-3

13.3x+2x+6=-15

5x+6=-15

5x=-15-6

x=-21/5

14.4=-2(x+3)

4=-2x-6

4+6=-2x

10/-2=x

-5=x

15.27=46+2x-x

27=46+x

27-46=x

-19=x

7 0
3 years ago
Read 2 more answers
Four students are planning a camping trip for Labor Day weekend. They are expecting 8 additional friends to attend. Refer to the
cupoosta [38]
Answer: $27.50

Explanation:

4 students + 8 friends = 12 people altogether

$330.60/12 = $27.50

Therefore, it’s going to cost approximately $27.50 per person.
3 0
4 years ago
A vending machine automatically pours soft drinks into cups. The amount of soft drink dispensed into a cup is normally distribut
labwork [276]

Answer:

a) P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

b)P(X

And we can find this probability using the standard normal table or excel:

P(Z

c) For this case we have a total of 868 cups and we know that the fraction of cups that will be overflow is 0.159, so then the expected number of cups overflow would be:

N = 868*0.159= 138.012 \approx 138

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the amount of soft frink of a population, and for this case we know the distribution for X is given by:

X \sim N(7.6,0.4)  

Where \mu=7.6 and \sigma=0.4

We are interested on this probability

P(X>8)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>8)=P(\frac{X-\mu}{\sigma}>\frac{8-\mu}{\sigma})=P(Z>\frac{8-7.6}{0.4})=P(Z>1)

And we can find this probability using the complement rule and the standard normal table or excel:

P(Z>1)=1-P(Z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the standard normal table or excel:

P(Z

Part c

For this case we have a total of 868 cups and we know that the fraction of cups that will be overflow is 0.159, so then the expected number of cups overflow would be:

N = 868*0.159= 138.012 \approx 138

6 0
4 years ago
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