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2 years ago

Use a for your variable. 13 less than 4 times a number is greater than 75 what's the answer

Mathematics

2 answers:

tiny-mole [99]2 years ago

8 0

Answer:

13-4a>75 if this is your question then your answer is a< -31/2 or a< -15.5

If you need it in interval notation the answer is (-infinity , -31/2)

Hope This Helps! Also sorry I couldn't put the infinity sign.

sammy [17]2 years ago

6 0

Answer:

Let n = the number

4n - 9 = n

3n = 9

n = 3

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Given fx = vneiolfjwijfewjfwe

Sindrei [870]

Part (a)

$f(3)=5(3)-3=\boxed{12}$

Part (b)

$5x-3=-28 \\ \\ 5x=-25 \\ \\ x=\boxed{-5}$

5 0

1 year ago

Need help number the answers bye order plz

iragen [17]

OK so here it goes:
1a. 10³
1b. 10²
1c. 10(tiny 6)
1d. 10³
1e. 10(tiny6)
1f. 10(tiny 5)

2a. 400
2b. 640,000
2c. 5,400
2d. 5,301,000
2e. is it multipcation or addition
2f. 607,200
2g. 0.948
2h. 0.0094

3a) 0.02, 0.2, 2, 20, 200, 2000
3b) 3,400,000 ; 34,000; 340, 3.4, 0.034
3c) 85,700; 8,570; 857, 85.7, 8.57, 0.857
3d) 444, 4440, 44,400; 440,000; 4,400,000; 44,000,000
3e) 0.95, 9.5, 950, 95,000; 950,000; 9,500,000

Hope this helps.

6 0

2 years ago

David has 4 cages of hamsters. The second cage has 1/2 as many hamsters as the first. The third cage has 1/2 as many hamsters as

atroni [7]

Answer:

1/4 of the first cage

8 0

2 years ago

Read 2 more answers

A man (M) is standing on the bank of a river that is 0.9 miles wide. He wants to reach a house (B) on the opposite shore that is

atroni [7]

Answer:

The distance between the hose and the point (P) is 0.9 miles

Step-by-step explanation:

Here we have

Speed of rowing the boat = 3 mph

Speed of waling = 4.5 mph

Since the speed of walking is more than that of to row the boat, the location of where he should dock his boat in order to minimize the total time he would need to reach the house is the shortest distance across the river to the house

Therefore the location of the point (P) should be directly opposite the house across the water and the distance id 0.9 miles.

3 0

2 years ago

A scientist removed a sample of 39.1 grams of a chemical from a container. The sample was 5 3/4 grams less than 3/10 of the tota

Oksanka [162]

The first thing we must do for this case is to define variables:

x: the total mass of the chemical in the container

y: a sample of a chemical from a container

We have the following equation:

y = (3/10) x - 5 3/4

Then, for y = 39.1 we have:

39.1 = (3/10) x - 5 3/4

Clearing x:

(3/10) x = 39.1 + 5 3/4

(3/10) x = 44.85

x = (10/3) * (44.85)

x = 149.5 grams

Answer:

the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:

x = 149.5 grams.

3 0

2 years ago

Use a for your variable. 13 less than 4 times a number is greater than 75 what's the answer ​

Use a for your variable. 13 less than 4 times a number is greater than 75 what's the answer