Answer:
C. -5
Step-by-step explanation:
for g(x) =ax and f(x) = x, both are linear function. There is nothing to be upward or downward and both are lines nothing to compare its narrowness.
If g(x) = ax² vs f(x) = x²
Then a = -5 is the answer (-: downward and 5: vertical stretch)
There must be 2 lines on every plane because you need a y-axis and an x-axis.
Answer:
Mary has the better deal
Step-by-step explanation:
Jennifer's $1.35 * 12 = $16.20
Mary's 12 flowers = $15.96
The first statement is true.
The second statement is false.
The third statement is true.
∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
