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3 years ago

Farmer gray has 30 flowerpots. He plants 10 seeds in each pot. How many seeds does he plant?

Mathematics

2 answers:

Elenna [48]3 years ago

5 0

He has planted 300 seeds. It is 30 flowerpots with 10 seeds in each which is 10 x 30.

frozen [14]3 years ago

3 0

If he puts tens in each that's 10x30 so its 300
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Identify square root of 3 as either rational or irrational, and approximate to the tenths place.

dmitriy555 [2]

Answer:

It is an irrational number, $\sqrt{3}$ as a decimal rounded to the tenth place is 1.7

Step-by-step explanation:

All square roots are irrational numbers

3 0

3 years ago

Read 2 more answers

Para hacer 600 m de una obra, 30 obreros han trabajado 12 dias a razon de 10 horas diarias. ¿Cuantos dias necesitaran 36 obreros

Gwar [14]

Respuesta:

25 días

Explicación paso a paso:

Dado :

escenario 1

Área = 600 m

Número de días = 12

Número de trabajadores = 30

Tasa = 6

Escenario 2:

Área = 900 m

Número de días = n

Número de trabajadores = 36

Tasa = 6

Igualar los parámetros en cada escenario:

12 / n = 36/30 * 6/10 * 600/900

12 / n = 6/5 * 3/5 * 2/3

12 / n = 6/5 * 1/5 * 2/1

12 / n = 12/25

12 * 25 = 12n

300 = 12n

n = 300/12

n = 25 días

7 0

3 years ago

Jordan is trying to figure out how much carpeting he will need for his game room.Which type of measure is this

Agata [3.3K]

You will need to add all the dimensions together, also know as perimeter

3 0

3 years ago

What is the recursive formula for this sequence? 24,20,16,12

kirza4 [7]

Answer:

28 - 4n

Step-by-step explanation:

What is the recursive formula for this sequence? 24,20,16,12

the sequence first term is 24

a= 24

Common difference (d) = T2 - T1 = T3 - T2

d = 20-24 = 16 -20

d = -4

Formula for nth term

Tn = a + (n-1)d

Tn = 24 + (n -1)-4

Tn = 24 -4n + 4

Tn = 28 - 4n

= 28 - 4n

I hope this was helpful, please mark as brainliest

7 0

3 years ago

A) Use the limit definition of derivatives to find f’(x)

Ann [662]

$\text{Given that,}\\\\f(x) = \dfrac{ 1}{3x-2}\\\\\text{First principle of derivatives,}\\\\f'(x) = \lim \limits_{h \to 0} \dfrac{f(x+h) - f(x) }{ h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{1}{3(x+h) - 2} - \tfrac 1{3x-2}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{1}{3x+3h -2} - \tfrac{1}{3x-2}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{3x-2-3x-3h+2}{(3x+3h-2)(3x-2)}}{h}\\\\\\$

$~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{-3h}{(3x+3h-2)(3x-2)}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{-3h}{h(3x+3h-2)(3x-2)}\\\\\\~~~~~~~~=-3 \lim \limits_{h \to 0} \dfrac{1}{(3x+3h-2)(3x-2)}\\\\\\~~~~~~~~=-3 \cdot \dfrac{1}{(3x+0-2)(3x-2)}\\\\\\~~~~~~~~=-\dfrac{3}{(3x-2)(3x-2)}\\\\\\~~~~~~~=-\dfrac{3}{(3x-2)^2}$

$\text{Given that,}~\\\\f(x) = \dfrac{1}{3x-2}\\\\\textbf{Power rule:}\\\\\dfrac{d}{dx}(x^n) = nx^{n-1}\\\\\textbf{Chain rule:}\\\\\dfrac{dy}{dx} = \dfrac{dy}{du} \cdot \dfrac{du}{dx}\\\\\text{Now,}\\\\f'(x) = \dfrac{d}{dx} f(x)\\\\\\~~~~~~~~=\dfrac{d}{dx} \left( \dfrac 1{3x-2} \right)\\\\\\~~~~~~~~=\dfrac{d}{dx} (3x-2)^{-1}\\\\\\~~~~~~~~=-(3x-2)^{-1-1} \cdot \dfrac{d}{dx}(3x-2)\\\\\\~~~~~~~~=-(3x-2)^{-2} \cdot 3\\\\\\~~~~~~~~=-\dfrac{3}{(3x-2)^2}$

8 0

2 years ago