Answer:
Go through the explanation you should be able to solve them
Step-by-step explanation:
How do you know a difference of two square;
Let's consider the example below;
x^2 - 9 = ( x+ 3)( x-3); this is a difference of two square because 9 is a perfect square.
Let's consider another example,
2x^2 - 18
If we divide through by 2 we have:
2x^2/2 -18 /2 = x^2 - 9 ; which is a perfect square as shown above
Let's take another example;
x^6 - 64
The above expression is the same as;
(x^3)^2 -( 8)^2= (x^3 + 8) (x^3 -8); this is a difference of 2 square.
Let's take another example
a^5 - y^6 ; a^5 - (y ^3)^2
We cannot simplify a^5 as we did for y^6; hence the expression is not a perfect square
Lastly let's consider
a^4 - b^4 we can simplify it as (a^2)^2 - (b^2)^2 ; which is a perfect square because it evaluates to
(a^2 + b^2) ( a^2 - b^2)
Kid-A A1,A2,A3,A4,A5
Kid-B B1,B2,B3,B4,B5
Kid-C C1,C2,C3,C4,C5
Kid-D D1,D2,D3,D4,D5
Ellen E1,E2,E3,E4,E5
7x + y = -5
-7x both sides
y= -7x-5
slope is -7
-3+7=4 y intercept is 4
y=-7x+4
(a) We use product rule here. P'(x) = F'(x)G(x) + F(x)G'(x).P'(2) = F'(2)G(2) + F(2)G'(2). Looking at the graph: F'(2) = 0, F(2) = 3, G'(2) = 1/2, G(2) = 2. Hence, P'(2) = (0)(2) + (3)(1/2) = 1.5.
(b) Using the quotient rule here. Q'(x) = (G(x)F'(x) - F(x)G'(x))/G(x)^2. Looking at the graph: F'(7) = 1/4, F(7) = 5, G'(7) = -3/2, G(7) = 1. Q'(7) = (1*1/4-5*(-3/2))/1^2 = 31/4 = 7.75.
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It is the second choice
hope this helps:)
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