Claims what you are going to talk about
Answer:
The answer is below
Explanation:
The half life of a substance is the time required by that substance to reduce to half of its initial value. The half life is calculated using the formula:
![N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\where\ N(t)=quantity\ of\ substance \ remaining, N_o=initial\ quantity\\of\ substance, t=time\ and \ t_\frac{1}{2}=half\ life\ of\ substance](https://tex.z-dn.net/?f=N%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7Bt%7D%7Bt_%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5C%5C%5C%5Cwhere%5C%20N%28t%29%3Dquantity%5C%20of%5C%20substance%20%5C%20remaining%2C%20N_o%3Dinitial%5C%20quantity%5C%5Cof%5C%20substance%2C%20t%3Dtime%5C%20and%20%5C%20t_%5Cfrac%7B1%7D%7B2%7D%3Dhalf%5C%20life%5C%20of%5C%20substance)
Given that t = 87 years, half life = 29 years, therefore the quantity of strontium-90 left is:
![N(t)=N_o(\frac{1}{2} )^\frac{87}{29} \\\\N(t)=N_o(\frac{1}{2} )^\frac{t}{t_\frac{1}{2} } \\\\N(t)=N_o(\frac{1}{2} )^3\\\\N(t)=\frac{1}{8} N_o](https://tex.z-dn.net/?f=N%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7B87%7D%7B29%7D%20%5C%5C%5C%5CN%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7Bt%7D%7Bt_%5Cfrac%7B1%7D%7B2%7D%20%7D%20%5C%5C%5C%5CN%28t%29%3DN_o%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E3%5C%5C%5C%5CN%28t%29%3D%5Cfrac%7B1%7D%7B8%7D%20N_o)
That is one-eight of Strontium 90 would be left after 87 years
The equation is glucose + oxygen = carbon dioxide + water + energy