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4 years ago

H3C6H507(aq) + 3NaHCO3(aq) - Na3C6H5O7(aq) + 3C02(g) + 3__

Chemistry

2 answers:

Assoli18 [71]4 years ago

7 0

Answer:

The missing compound is H2O

Explanation:

Step 1: Data given

H3C6H507(aq) + 3NaHCO3(aq) → Na3C6H5O7(aq) + 3C02(g) + 3

The reactants are : H3C6H507(aq) + 3NaHCO3(aq)

The products are: Na3C6H5O7(aq) + 3C02(g) and ....

Step 2:

The reactants have 11 H atoms (8 in H3C6H5O7(aq) and 3 in NaHCO3(aq))

The products have 5H atoms (in Na3C6H5O7(aq))

Here we miss 6 H atoms

The reactants have 3 Na atoms (in 3NaHCO3(aq))

The products have 3 Na atoms (in Na3C6H5O7(aq))

The amount of Na atoms on both sides is balanced. This means the missing compound is not NaOH

The reactants have 16 O atoms (7 in H3C6H507(aq) and 9 in 3NaHCO3(aq))

The products have 13 O atoms (7 in Na3C6H5O7(aq) and 6 in 3C02(g))

Here we miss 3 O atoms

The reactants have 9 C atoms (6 in H3C6H507(aq) and 3 in 3NaHCO3(aq))

The products have 9 C atoms (6 in Na3C6H5O7(aq) and 3 in 3CO2(g))

The amount of C is balanced on both sides.

This means the missing compound will not have a C atom.

Option 1 (COH2) and option 4 (COOH) are not possible

The missing compound is H2O

zavuch27 [327]4 years ago

6 0

Answer: 3 H₂O

Explanation:

This is an example of a common chemical reaction

ACID + CARBONATE --> SALT + WATER + CARBON DIOXIDE which implires

CITRIC ACID + SODIUM BICARBONATE ----> SODIUM CITRATE + WATER + CARBON DIOXIDE .

The full chemical equation is given by

H3C6H5O7(aq) + 3NaHCO3(aq) --> Na3C6H5O7(aq) + 3CO2(g) + 3H2O(l)

The reaction produces a fizz due to the release of carbon dioxide which can be also seem when an Alka-Seltzer® tablet is dissolved in water.

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iragen [17]

Answer:

The values of n, p and q are 314, 0.12 and 0.88 respectively.

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n is the number of subjects given a placebo. The value of n is 314.

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3 years ago

What percentage of gases that make up the atmosphere are found in the troposphere and atmosphere combined?

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3 years ago

Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta

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Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]$

Putting the values we get :

$\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]$

$\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]$

$\Delta H=-5314.8kJ$

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = $\frac{5314.8}{2}\times 1=2657.4kJ$

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

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3 years ago

The density of toluene (C7H8) is 0.867 g/mL, and the density of thiophene (C4H4S) is 1.065 g/mL. A solution is made by dissolvin

nadya68 [22]

Answer:

(a) 0.039

(b) 0.384 M

Explanation:

We have the following data:

d(C₇H₈) = 0.867 g/mL

d(C₄H₄S) = 1.065 g/mL

V(C₇H₈) = 250.0 mL

mass(C₄H₄S) = 8.10 g

(a) The mole fraction of C₄H₄S in the solution is the number of moles of C₄H₄S divided into the total moles of the solution:

X(C₄H₄S) = moles C₄H₄S/ total moles

To calculate the moles, we need the molecular weight (MW) of each compound:

MW(C₄H₄S) = (4 x 12 g/mol) + (4 x 1 g/mol) + 32 g/mol = 84 g/mol

MW(C₇H₈) = (7 x 12 g/mol) + (8 x 1 g/mol) = 92 g/mol

Thus, we calculate the moles of C₄H₄S by dividing the mass into the MW(C₄H₄S):

moles C₄H₄S = mass(C₄H₄S)/MW(C₄H₄S)= 8.10 g/(84 g/mol) = 0.096 moles

Then, we have to calculate the moles of C₇H₈. First, we need the mass, obtained from the product of the density by the volume:

mass(C₇H₈)= d(C₇H₈) x V(C₇H₈) = 0.867 g/mL x 250.0 mL = 216.75 g

Thus, we divide the mass of C₇H₈ into the MW to calculate the moles of C₇H₈:

moles C₇H₈ = mass(C₇H₈)/MW(C₇H₈) = 216.75 g/(92 g/mol) = 2.35 moles

The total moles is obtained from the addition of the moles of the solute (C₄H₄S) and the solvent (C₇H₈):

total moles = moles C₄H₄S + moles C₇H₈ = 0.096 moles + 2.35 moles = 2.45 moles

Finally, we calculate the mole fraction of C₄H₄S:

X(C₄H₄S) = moles C₄H₄S/ total moles = 0.096 moles/2.45 moles = 0.039

(b) The molarity of C₄H₄S is calculated as follows:

M(C₄H₄S) = moles C₄H₄S/1 liter solution

Assuming that the total volume of the solution is the volume of solvent (C₇H₈), we calculate the molarity of C₄H₄S by dividing the moles into the volume of solvent in liters:

V(C₇H₈) = 250.0 mL = 0.250 L

M(C₄H₄S) = 0.096 moles/(0.250 L) = 0.384 mol/M = 0.384 M

(c) Assuming that the volumes of solute and solvent are additive, we can add the volumes of C₄H₄S and C₇H₈. First, we need the volume of C₄H₄S, which can be calculated from the mass and density:

V(C₄H₄S) = mass(C₄H₄S)/ d(C₄H₄S) = 8.10 g/(1.065 g/mL) = 7.606 mL = 0.0076 L

Now, we add the volumes:

total volume = V(C₇H₈) + V(C₄H₄S) = 0.250 L + 0.0076 L = 0.2576 L

Finally, we recalculate the molarity of C₄H₄S:

M(C₄H₄S)= moles C₄H₄S/ total volume = 0.096 moles/0.2576 L = 0.373 M

7 0

3 years ago

A gas temperature of 14 C and a volume of 4.5L. If the temperature is raised ot 29 C and the pressure is not changed, what is th

zhenek [66]

T1 = 14⁰C = 273 +14= 287 K
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P = constant

T1/T2 = V1/V2
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3 years ago