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Andreas93 [3]
3 years ago
6

Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta

.Hf = –241.82) in the reaction: 2 upper C subscript 4 upper H subscript 10 (g) plus 13 upper O subscript 2 (g) right arrow 8 upper C upper O subscript 2 plus 10 upper H subscript 2 upper O (g). What is the enthalpy of combustion, per mole, of butane? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants.
Chemistry
1 answer:
shusha [124]3 years ago
3 0

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The expression for enthalpy change is,

\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]

Putting the values we get :

\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]

\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]

\Delta H=-5314.8kJ

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = \frac{5314.8}{2}\times 1=2657.4kJ

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

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F(x)=-1/x
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Domain of (f/g)(x):  ??

1We find out the domain of f(x):
f(x) is a rational function, therefore can take real values if the denominator is not ("0"), therefore the domain of f, will be all values excpet "0"
Domain of  f: (-∞,0)U(0,+∞); 


                                                          o
----------------------------------------------O-------------------------------------------
←-------- -∞                                                               +∞           ----------→


g(x) is a radical square root  function, therefore the radicand have to be greater than o equal to "0"
3x-9≥0
3x≥9
x≥3

                                                         3
.........................................................Ф--------------------------------
←--------- - ∞                                                        +∞ -----------→
          
(f/g)(x) = (-1/x) / (√(3x-9)) is a rational function with a square root in the denominator,also the square root don´t take the value of "0";
Therefore:
3x-9>0
3x>9
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The domain of the function (f/g)(x) only can take the values found in all three domains at once.
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............................................................0---------------------------------
←--------- -∞                                                          +∞-------------→

Answer: (3,+∞)
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Explanation:

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We have the final answer as

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