Answer : The moles of given compound is, 0.064 mole
Explanation : Given,
Mass of given compound = 40 g
Atomic mass of X = 50 amu
Atomic mass of Y = 45 amu
Atomic mass of Z = 10 amu
First we have to calculate the molar mass of given compound.
The given compound formula is, 
Molar mass of = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)
Molar mass of = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol
Now we have to calculate the moles of given compound.
Thus, the moles of given compound is, 0.064 mole
Answer:
ΔH3 = -110.5 kJ.
Explanation:
Hello!
In this case, by using the Hess Law, we can manipulate the given equation to obtain the combustion of C to CO as shown below:
C(s) + 1/2O2(g) --> CO(g)
Thus, by letting the first reaction to be unchanged:
C(s) + O2(g)--> CO2 (g) ; ΔH1 = -393.5 kJ
And the second one inverted:
CO2(g) --> CO(g) + 1/2O2(g) ; ΔH2= 283.0kJ
If we add them, we obtain:
C(s) + O2(g) + CO2(g) --> CO(g) + CO2 (g) + 1/2O2(g)
Whereas CO2 can be cancelled out and O2 subtracted:
C(s) + 1/2O2(g) --> CO(g)
Therefore, the required enthalpy of reaction is:
ΔH3 = -393.5 kJ + 283.0kJ
ΔH3 = -110.5 kJ
Best regards!
Okay... what are the following
<span>In this particular item, we are to determine how we call the acidic fluid-like substance that is formed after the food in the stomach is broken down by a powerful acid. The answer to this question is CHYME. The powerful acid that is referred in this item is more specifically gastric juices. </span>
