Answer:
y=4x+7
Step-by-step explanation:
You can find the slope of the line by using the formula of change and y over change in x. ∆y/∆x OR (y2-y1)/(x2-x1)
11-3=8
1--1=2
8/2=4
Let's plug in a y value 3.
3=4*-1+b
b=7
Once you found b rewrite your equation in slope intercept form.
y=4x+7
You can check this equation by plugging in the unused coordinate (1,11) and find it balances.
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Answer: How find the volume of a triangular pyramid?
Triangular pyramid volume formula
In words: the volume of a triangular pyramid is one-third of the product of the base area and the pyramid's height
Step-by-step explanation:
Now in mathematical terms Use the formula for the volume of a triangular pyramid: V=13Ah , where A = area of the triangular base, and H = height of the pyramid.
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Answer:
h(k+6) if h(x)=15x+6
h(k+6)=15(k+6)+6=15k+90+6=15k+96
Answer:
The expected total amount of time the operator will spend on the calls each day is of 210 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n-values of normal variable:
Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is
and the standard deviation is 
Calls to a customer service center last on average 2.8 minutes.
This means that 
75 calls each day.
This means that 
What is the expected total amount of time in minutes the operator will spend on the calls each day
This is M, so:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.