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4 years ago

4 / 500 in scientific notation would be?

Mathematics

1 answer:

Lubov Fominskaja [6]4 years ago

3 0

4/500=0.008

scientific notation form = 8 x 10^9

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Pls help me with 15-19 pls

EleoNora [17]

Answer:

-4

Step-by-step explanation:

3 0

3 years ago

What is the slope of the line that passes through the points (-2,3) and (-1,8)

yaroslaw [1]

Answer:

Slope m = 5

Step-by-step explanation: sorry if Im wrong but If i am then it is just 5:)

5 0

2 years ago

How do you do this question?

Bess [88]

"The function is decreasing":

This means the slope of the function will be negative at the given point. Anywhere the line is going down, from left to right, is decreasing. This eliminates choices A and C.

"The function is concave down":

This means the curve of the function will be open down (think of an upside down u). This eliminates choice E.

"f(x)>0":

This is anywhere the curve is above the x axis. This eliminates choice D.

The answer is Choice B) x=2.

Hope this helps!!

3 0

4 years ago

june has a savings account with an annual simple intrest rate of 2.6% she hopes to gain $6,500. in interest over a period of ele

natima [27]

To solve this, let's use the variable 'x' to represent the money invested:

11(0.026(x)) = 6500

0.286x = 6500

Divide:

x = 227272.7272...

We can round up:

x = 227272.73

June has to invest $227272.73

6 0

4 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

3 years ago